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weeeeeb [17]
3 years ago
7

Which element is oxidized in the reaction below? fe(co)5 (l) + 2hi (g) → fe(co)4i2 (s) + co (g) + h2 (g)

Chemistry
1 answer:
Hunter-Best [27]3 years ago
7 0
The element which is oxidized  in  the  reaction below 
that is

Fe(Co)5  (l) +  2 Hi (g)=  Fe (CO)4 i2(s) +Co (g)+H2 (g)  is

 Fe   this is because   fe in Fe(CO)5  compound move from oxidation state  of  Positive five (5^+)  to  oxidation  state  of  positive  six ( 6^+)  in Fe(CO)4i2  compound.   fe  is  oxidized  by Hi  while  Hi  itself is  reduced  by   Fe,therefore Fe  act as a  reducing agent
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<u>Answer:</u> The solubility of Cd_3(PO_4)_2 in water is 1.18\times 10^{-7}mol/L

<u>Explanation:</u>

The balanced equilibrium reaction for the ionization of cadmium phosphate follows:

Cd_3(PO_4)_2\rightleftharpoons 3Cd^{2+}+2PO_4^{3-}

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The expression for solubility constant for this reaction will be:

K_{sp}=[Cd^{2+}]^3[PO_4^{3-}]^2

We are given:

K_{sp}=2.5\times 10^{-33}

Putting values in above equation, we get:

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Hence, the solubility of Cd_3(PO_4)_2 in water is 1.18\times 10^{-7}mol/L

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