if the distance between two objects is decreased to one fourth of the original distance how will the decrease change the force o
f attraction between the objects
1 answer:
F = GMm/r²
<span>The relationship between F and r is an inverse one. So if the distance r decreases, to 1/4 the original distance:
Let F </span>α 1/r²
F = k/r²
or F₂ / F₁ = (r₁ / r₂)²
If r is decreased to 1/4,
F₂ / F₁ <span>= (r₁ / r₂)²
</span>
F₂ / F₁ = (r₁ / (1/4r₁)<span> )²
</span>
F₂ / F₁ <span>= (4)²
</span>
F₂ / F₁ <span>= 16
</span>
F₂ <span>= 16F</span>₁
The new force of attraction would be 16 times the former value.
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