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atroni [7]
3 years ago
13

Many of today’s mathematicians use computers to test cases that ___

Physics
1 answer:
vekshin13 years ago
7 0

Many of today’s mathematicians use computers to test cases that are either too time-consuming or involve too many variables to test manually, allowing the exploration of theoretical issues that were impossible to test a generation ago.

Answer: Option A

<u>Explanation:</u>

One of the most useful inventions in scientific world are the computers. We can use different programming language and create programs in them. These programs help other to solve difficult problems. Most of the theoretical problems in science can be solved by using these programming features in computer within a specific time limit.

Otherwise, earlier mathematician used to take months to solve a complex mathematical problem manually, but now with the inclusion of computers, the mathematician can solve the problems containing more number of variables or other theoretical issues.

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In the fabrication of an electrical extension cord, the manufacturer wants to reduce the overall resistance of the wires in the
Bezzdna [24]

Answer:

Option B is correct.

Explanation:

The resistance of a material or wire is represented by the formula below.

R=(ρL)/A

where

  • R is resistance of wire
  • ρ is the resistivity of the material
  • A is the cross sectional area of wire
  • L is length of wire

Resistance increases with increase in length and resistivity which means options C and D are wrong.

A=(πd^{2})/4

An increase in diameter will result in a proportional increase in area

From the resistance formula, an increase in area will cause a reduction in the resistance of the material.Thus increased diameter of wire will lower the resistance of wire. Option B is correct

Have a great day

5 0
3 years ago
PLS HELP I WILL GIVE BRAINLIEST TO FIRST ANSWER
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Hope this is helpfull

Explanation:

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8 0
3 years ago
Calculate the power transfer when a pump moves 50kg of water through a vertical height of 8meters in 5seconds (take g =10meters
Vika [28.1K]

Hi there!

Recall the following relationships:

W = \Delta U = mg\Delta h\\\\P = \frac{W}{t}

W = Work (J)

U = Potential Energy (J)

m = mass (kg)

g = acceleration due to gravity (9.8 m/s²)

h = height (m)

t = time (s)

Begin by calculating the work:

W = 50(10)(8) = 4000 J

Now, divide by the time to solve for power:

P = \frac{4000}{5} = \boxed{800W}

**W is the unit for power (Watts).  Be careful not to get the two confused.

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