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2 years ago

8

Willing to give out brainliest... A vat of ethyl alcohol expands by 0.00823 m^ 3 when the temperature is raised by 44.8 °C . Wha

t was the original volume of the alcohol ?

1 answer:

scoundrel [369]2 years ago

4 0

Answer: 0.164

Explanation:

the coefficient for ethyl alcohol b is 1120x10^-6

so (0.00823)/ (1120x10^-6)(44.8) gives you your answer: 0.164

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When two point charges are a distance d part, the electric force that each one feels from the other has magnitude F. In order to

Serjik [45]

Answer:

E) d/sqrt2

Explanation:

The initial electric force between the two charge is given by:

$F=k\frac{q_1 q_2}{d^2}$

where

k is the Coulomb's constant

q1, q2 are the two charges

d is the separation between the two charges

We can also rewrite it as

$d=\sqrt{k\frac{q_1 q_2}{F}}$

So if we want to make the force F twice as strong,

F' = 2F

the new distance between the charges would be

$d'=\sqrt{k\frac{q_1 q_2}{(2F)}}=\frac{1}{\sqrt{2}}\sqrt{k\frac{q_1 q_2}{(2F)}}=\frac{d}{\sqrt{2}}$

so the correct option is E.

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2 years ago

The process of reflection is most similar to _____.

Arte-miy333 [17]

Answer:

C.transmission

Explanation:

Scattering is everywhere

Absorption is to remove

3 0

3 years ago

A car travels north at 30 m/s for one half hour. It then travels south at 40 m/s for 15 minutes. The total distance the car has

kari74 [83]

Answer:

xtotal = 90km

displacement = 18km N

Explanation:

To find the total distance traveled by the car, you first calculate the distance traveled by the car when it travels to north. You use the following formula:

$x=vt$ (1)

x: distance

v: speed of the car = 30 m/s

t: time = one half hour

In order to calculate the distance you convert the time from hours to seconds:

$t=0.5\ h*\frac{3600s}{1\ h}=1800s$

Then, you replace the values of t and v in the equation (1):

$x=(30m/s)(1800s)=54000m$ (2)

Next, you calculate the distance traveled by the car when it travels to south:

$x'=v't'\\\\v'=40\frac{m}{s}\\\\t'=15\ min$

You convert the time from minutes to seconds:

$t'=15\ min*\frac{60s}{1min}=900s$

$x'=(40m/s)(900s)=36000m$

Finally, you sum both distances x and x':

$x_{total}=x+x'=54000m+36000m=90000m=90km$

The total distance traveled by the car is 90km

The total displacement is the final distance of the car respect to the starting point of the motion. This is calculated by subtracting x' to x:

$d=x-x'=54000m-36000m=18000m=18km$

The total displacement of the car is 18km to the north from its starting point of motion.

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2 years ago

A 15.0-gram lead ball at 25.0°C was heated with 40.5 joules of heat. Given the specific heat of lead is 0.128 J/g∙°C, what is th

mr Goodwill [35]

Answer:

$T=4985.5^{\circ}K$

Explanation:

The equation that relates heat Q with the temperature change $T-T_0$ of a substance of mass <em>m </em>and specific heat <em>c </em>is $Q=mc(T-T_0)$ .

We want to calculate the final temperature <em>T, </em>so we have:

$T=\frac{Q}{mc}+T_0$

Which for our values means (in this case we do not need to convert the mass to Kg since <em>c</em> is given in g also and they cancel out, but we add $273^{\circ}$ to our temperature in $^{\circ}C$ to have it in $^{\circ}K$ as it must be):

$T=\frac{Q}{mc}+T_0=\frac{40.5J}{(15g)(0.128J/g^{\circ}C)}+(298^{\circ}K)=4985.5^{\circ}K$

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Viktor [21]

Answer:

1.351 A

Explanation:

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2 years ago