1.) core- the central region where nuclear reactions consume hydrogen to form helium
2.) radiative zone- the section of solar interior between the innermost core and the outer convective zone.
3.) convection zone- where light (photons) is created.
4.) photosphere- the visible surface of the sun that we are most familiar with
5.) chromosphere- second most outer layer of the sun. due to low density it is relatively transparent and only apparent during eclipses.
6.) corona- an aura of plasma that surrounds the sun and other stars but is usually hidden by the bright light of the sun’s surface.
Answer:
A. 50 Hz
B. 2 m/s
Explanation:
We'll begin by converting 20 ms to s. This can be obtained as follow:
1000 ms = 1 s
Therefore,
20 ms = 20 ms × 1 s / 1000 ms
20 ms = 0.02 s
Next, we shall convert the value of the wavelength (i.e 4cm) to m. This can be obtained as follow:
100 cm = 1 m
Therefore,
4 cm = 4 cm × 1 m / 100 cm
4 cm = 0.04 m
A. Determination of the frequency.
Period (T) = 0.02 s
Frequency (f) =?
f = 1 / T
f = 1 / 0.02
f = 50 Hz
Therefore, the frequency of the wave is 50 Hz
B. Determination of the velocity.
Wavelength (λ) = 0.04 m
Frequency (f) = 50 Hz
Velocity (v) =?
v = λf
V = 0.04 × 50
v = 2 m/s
Therefore, the velocity of the wave is 2 m/s
Answer:
the location of the center of gravity for the entire body is 1.08 m
Explanation:
Given the data in the question;
w1 = 458 N, y1 = 1.34 m
w2 = 120 N, y2 = 0.766 m
w3 = 89.8 N, y2 = 0.204 m
The location arrangement of the body part is vertical, locate the overall centre of gravity by simply replacing the horizontal position x by the vertical position y as measured relative to the floor.
so,
= (w1y1 + w2y2 + w3y3 ) / ( w1 + w2 + w3 )
so we substitute in our values
= (458×1.34 + 120×0.766 + 89.8×0.204 ) / ( 458 + 120 + 89.8 )
= 723.9592 / 667.8
= 1.08 m
Therefore, the location of the center of gravity for the entire body is 1.08 m
Answer:
53.64 m/s
Explanation:
Applying,
a = (v-u)/t............. Equation 1
Where a = acceleration of the car, v = final velocity of the car, u = initial velocity of the car, t = time.
make u the subject of the equation
u = v-at............. Equation 2
From the question,
Given: a = -12 mph/s = -5.364 m/s², t = 10 seconds, v = 0 m/s (comes to stop)
Substitute these values into equation 2
u = 0-(-5.364×10)
u = 0+53.64
u = 53.64 m/s
