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3 years ago

What does the slope on a speed vs. time graph represent

Physics

1 answer:

steposvetlana [31]3 years ago

5 0

Answer:

It represents the amount of speed per time or (x) for speed (y) for time so the slope would be like y/x

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I need help real quick. Please help me!!

dimaraw [331]

<h3><u>Answer;</u></h3>

D) Standing wave

<h3><u>Explanation;</u></h3>

Standing wave also called stationary wave is a wave which oscillates in time but whose peak amplitude profile does not move in space.
A standing wave pattern is a vibrational pattern created within a medium when the vibrational frequency of the source causes reflected waves from one end of the medium to interfere with incident waves from the source.
Examples of standing waves include the vibration of a violin string and electron orbitals in an atom.

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3 years ago

Using your Periodic Table, which element below has the smallest atomic radius? A.) Sodium, B.) Chlorine, C.) Phosphorus, D.) Iro

egoroff_w [7]

Explanation:

Chlorine is the smallest atomic radius

6 0

3 years ago

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Ten point on important of sports and games in human life

pishuonlain [190]

They make your muscles stronger and keep the bones, heart, and lungs in good condition. It implies that you have less chance of blood clotting and heart attack. one can balance his mood well and is likely to experience less stress in life.It also helps us to practice discipline.

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3 years ago

If you could live any where except for where you are now where would you live

laila [671]

Answer:

I would live in the Atlantic ocean on a lux liner

Explanation:

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3 years ago

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After being struck by a bowling ball, a 1.8 kg bowling pin sliding to the right at 5.0 m/s collides head-on with another 1.8 kg

kaheart [24]

Answer:

a) v₂ = 4.2 m/s

b) v₂ = 5 m/s

Explanation:

We will use the law of conservation of momentum here:

$m_1u_1+m_2u_2=m_1v_1+m_2v_2$

where,

m₁ = m₂ = mass of bowling pin = 1.8 kg

u₁ = speed of first pin before collsion = 5 m/s

u₂ = speed of second pin before collsion = 0 m/s

v₁ = speed of first pin after collsion = 0.8 m/s

v₂ = speed of second after before collsion = ?

Therefore,

$(1.8\ kg)(5\ m/s)+(1.8\ kg)(0\ m/s)=(1.8\ kg)(0.8\ m/s)+(1.8\ kg)(v_2)\\v_2 = 5\ m/s - 0.8\ m/s$

<u></u>

We will use the law of conservation of momentum here:

$m_1u_1+m_2u_2=m_1v_1+m_2v_2$

where,

m₁ = m₂ = mass of bowling pin = 1.8 kg

u₁ = speed of first pin before collsion = 5 m/s

u₂ = speed of second pin before collsion = 0 m/s

v₁ = speed of first pin after collsion = 0 m/s

v₂ = speed of second after before collsion = ?

Therefore,

$(1.8\ kg)(5\ m/s)+(1.8\ kg)(0\ m/s)=(1.8\ kg)(0\ m/s)+(1.8\ kg)(v_2)$

5 0

3 years ago