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3 years ago

Sound energy cannot travel through A vacuum,a wooden table,polluted air,pond water

Physics

1 answer:

FromTheMoon [43]3 years ago

6 0

Sound energy cannot travel through a vacuum.

Explanation:

Waves are periodic disturbance of the space, which travel carrying energy but not matter.

There are two types of waves:

Mechanical waves: mechanical waves propagate through the vibrations of the particles in a medium. Examples of mechanical waves are sound waves.
Electromagnetic waves: these waves consist of periodic oscillations of electric and magnetic fields, perpendicular to each other. These waves do not need a medium to propagate, so they can also travel in a vacuum.

In this problem, we are analyzing sound energy, which is the energy carried by sound waves. Sound waves are mechanical waves, so they need a medium to propagate: therefore, they cannot travel through a vacuum, since there is no medium.

So, sound energy cannot travel through a vacuum.

Learn more about waves:

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There is a single electron at a distance from the point charge. On which of the following quantities does the force on the elect

Anon25 [30]

Answer:

The following situations apply: A, B, D.

Explanation:

The following situations apply: A, B, D.

1.) The electric force on the electron depends on A because E= F/q and thus, F=kqq_o/r^2 Ta. As you can see, the electric force depends on r^2, which is the distance between the positive charge and the negative charge, squared.

2.) As for B, the electric force on the electron depends on its charge as you can see from equation above.

3.) As for C, mass doesn't appear anyway in the equation for Force, thus, the mass doesn't matter.

4.) For D, yes, see equation for Force.

5.) For E, no

6.) For F, r in the equation for the force refers to the distance between both charges, not the radius of either charge. Thus, F doesn't matter.

7.) For G, no.

6 0

3 years ago

Read 2 more answers

When you graph the motion of an object, you put _____ on the horizontal X axis and ____ on the vertical Y axis

wel

It depends upon the type of graph that you are talking about,

If the graph is Velocity - Time graph, then time lies on the X axis and speed on the Y axis.

If it is Distance - Time graph, the time lies on the X axis and distance on the Y axis.

But generally, it is ALWAYS TIME IN THE ‘X’ AXIS AND DISTANCE ON THE ‘Y’ AXIS.

Let me know if you have any doubts by either commenting or messaging me

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3 years ago

Calculate the amount of heat needed to raise the temperature of 200g of ice from-30°C 50C water. (C = .5 for ice, C 1 for water,

Nitella [24]

Answer: The amount of heat needed is 29000 Cal.

Explanation:

The process involved in this problem are:

$(1):H_2O(s)(-30^oC)\rightarrow H_2O(s)(0^oC)\\\\(2):H_2O(s)(0^oC)\rightarrow H_2O(l)(0^oC)\\\\(3):H_2O(l)(0^oC)\rightarrow H_2O(l)(50^oC)$

Now, we calculate the amount of heat released or absorbed in all the processes.

For process 1:

$q_1=mC_{p,s}\times (T_2-T_1)$

where,

$q_1$ = amount of heat absorbed = ?

m = mass of ice = 200 g

$T_2$ = final temperature = $0^oC$

$T_1$ = initial temperature = $-30^oC$

Putting all the values in above equation, we get:

$q_1=200g\times 0.5Cal/g^oC\times (0-(-30))^oC=3000Cal$

For process 2:

$q_2=m\times L_f$

where,

$q_1$ = amount of heat absorbed = ?

m = mass of water or ice = 200 g

$L_f$ = latent heat of fusion = 80 Cal/g

Putting all the values in above equation, we get:

$q_2=200g\times 80Cal/g=16000Cal$

For process 3:

$q_3=m\times C_{p,l}\times (T_{2}-T_{1})$

where,

$q_3$ = amount of heat absorbed = ?

m = mass of water = 200 g

$T_2$ = final temperature = $50^oC$

$T_1$ = initial temperature = $0^oC$

Putting all the values in above equation, we get:

$q_3=200g\times 1Cal/g^oC\times (50-0)^oC=10000Cal$

Calculating the total heat absorbed, we get:

$Q=q_1+q_2+q_3$

$Q=3000+16000+10000=29000Cal$

Hence, the amount of heat needed is 29000 Cal.

7 0

3 years ago

Middle C also known as "do" on the fixed do-solfege scale, is a note used when playing or singing music. The frequency of middle

saveliy_v [14]

Answer:

198.2m/s

Explanation:

Speed of a wave(v) is the product of the frequency of the wave (f) and its wavelength(¶).

Mathematically, v = f/¶

Given frequency of the middle C = 261.63Hz

Wavelength = 131.87cm

Converting this to meters we have;

131.87/100 = 1.32m

Speed of the sound = 261.63/1.32

Speed of the sound = 198.20m/s

Therefore the speed of sound for middle C is 198.2m/s

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4 years ago

A home gets its water from the public supply. Which of the following would be the best way for the homeowner to obtain a water-q

diamong [38]

The correct option is C.
Since the home gets its water from public supply, the best place to get the water quality report is from the local water treatment facility who processed the water. Water quality report is a document which summarizes information about the water sources that are used, detected contaminants, compliance observed, etc.

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4 years ago

Read 2 more answers