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3 years ago

What do 4 hydrogen and 2 oxygen atoms chemically react to

Chemistry

1 answer:

seropon [69]3 years ago

6 0

Answer:

2 molecules of water

Explanation:

In chemical reactions, molecules and compounds chemically combine to give products. This involves atoms combining by re-establishing bonding relationships.

4 hydrogen atoms is equivalent to 2 molecules of Hydrogen gas = H₂

2 oxygen atoms is the same as 1 oxygen molecule = O₂

This 2 molecules of hydrogen gas and 1 molecule of O₂ gas will combine to form 2 molecules of water chemically;

2H₂ + O₂ → 2H₂O

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What are the different phases of matter and their characteristics?

Novay_Z [31]

Answer:

The five phases of matter. There are four natural states of matter: Solids, liquids, gases and plasma. The fifth state is the man-made Bose-Einstein condensates. In a solid, particles are packed tightly together so they don't move much.

3 0

3 years ago

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What are two ways in which you can increase the potential energy of a marble on ramp

zlopas [31]

Answer:

You can make the ramp really steep and hold the marble at the top of it

Explanation:

6 0

3 years ago

The activation energy of a certain uncatalyzed biochemical reaction is 50.0 kJ/mol. In the presence of a catalyst at 37°C, the r

rodikova [14]

Answer:

E₁ ≅ 28.96 kJ/mol

Explanation:

Given that:

The activation energy of a certain uncatalyzed biochemical reaction is 50.0 kJ/mol,

Let the activation energy for a catalyzed biochemical reaction = E₁

E₁ = ??? (unknown)

Let the activation energy for an uncatalyzed biochemical reaction = E₂

E₂ = 50.0 kJ/mol

= 50,000 J/mol

Temperature (T) = 37°C

= (37+273.15)K

= 310.15K

Rate constant (R) = 8.314 J/mol/k

Also, let the constant rate for the catalyzed biochemical reaction = K₁

let the constant rate for the uncatalyzed biochemical reaction = K₂

If the rate constant for the reaction increases by a factor of 3.50 × 10³ as compared with the uncatalyzed reaction, That implies that:

K₁ = 3.50 × 10³

K₂ = 1

Now, to calculate the activation energy for the catalyzed reaction going by the following above parameter;

we can use the formula for Arrhenius equation;

$K=Ae^{\frac{-E}{RT}}$

If $K_1=Ae^{\frac{-E_1}{RT}} -------equation 1$ &

$K_2=Ae^{\frac{-E_2}{RT}} -------equation 2$

$\frac{K_1}{K_2} = e^{\frac{-E_1-E_2}{RT}$

$E_1= E_2-RT*In(\frac{K_1}{K_2})$

$E_1= 50,000-8.314*310.15*In(\frac{3.50*10^3}{1})$

$E_1 = 28957.39292$ $J/mol$

E₁ ≅ 28.96 kJ/mol

∴ the activation energy for a catalyzed biochemical reaction (E₁) = 28.96 kJ/mol

8 0

3 years ago

What is the pH of a 4.7 x 10-9 M HCl solution? *

ValentinkaMS [17]

11.21 or 2.93 I think

4 0

3 years ago

The smell of fresh cut pine is due in part to the cyclic alkene called pinene. Given the following data of pinene: Vapor pressur

Sveta_85 [38]

Answer: Heat of vaporization is 41094 Joules

Explanation:

The vapor pressure is determined by Clausius Clapeyron equation:

$ln(\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}(\frac{1}{T_1}-\frac{1}{T_2})$

where,

$P_1$ = initial pressure at 429 K = 760 torr

$P_2$ = final pressure at 415 K = 515 torr

= enthalpy of vaporisation = ?

R = gas constant = 8.314 J/mole.K

$T_1$ = initial temperature = 429 K

$T_2$ = final temperature = 515 K

Now put all the given values in this formula, we get

$\log (\frac{515}{760}=\frac{\Delta H}{2.303\times 8.314J/mole.K}[\frac{1}{429K}-\frac{1}{415K}]$

$\Delta H=41094J$

Thus the heat of vaporization is 41094 Joules

4 0

3 years ago