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kodGreya [7K]
3 years ago
7

Displacement vectors of 5 km north, 3 km east, 2 km south, and 3 km west combine to a total displacement of___. A. 3 km north..

B. 13 km west.. C. 0 km.. D. 2 km south..

Physics
2 answers:
True [87]3 years ago
8 0

Answer: Forces and Motion Unit Test (Connexus)

1. A. 3 km north

2.B. The airplane

3. C. at a particular instant

4. D. all of the above

5. C. the front seat of the car

6. C. inertia

7. C. one-third its weight on Earth's surface

8.D. gravity

9.D. all of the above

10. C. Pascal's principle

11.D. The weight of the balloon is less than the weight of the air displaced by the balloon

12.C. fluid displaced by the object

13. displacement

14.vector addition

15. positive

16 projectile

17. force,mass

18. increases

19.equally

These are the answers I put for the typed out Essay's

20. Speed is the distance traveled by an object where as, velocity is distance traveled by an object per unit time in a particular direction. Speed is a scaler quantity where as velocity is a vector quantity.

21. Acceleration is the rate of change, which means the change in velocity (vf-vi) with time(t) Where vf if the final velocity and vi is the initial velocity

22. Acceleration can be described as changes in speed, direction or both. The ball is moving at a constant speed, but its direction is changing continuously Because it's direction is changing, the ball is experiencing continuous acceleration.

23. For graph A, I can say that velocity is constant until it reaches time of 8 seconds and a constant velocity is again exhibited starting at time 12 seconds

24. For Graph B, the velocity is changing as time pass by since the slope is changing, At time of 2 seconds, graph A has greater velocity since it has a steeper slope.

25. 300 meters

26. Graph A shows greater velocity because Graph A has a steeper slope than Graph B.

27. 38 kg * 2.2 m/s=83.6 kg-m/s

28. The pressure inside the tube is greater than the pressure outside the tube because primarily of the smaller area of the tube. This increases up the pressure and let the fluid rise up.

29. The fertilizer is pushed up the tube.

Explanation: I hope this helps :)

kvv77 [185]3 years ago
4 0
The answer is <span>A. 3 km north
</span>
Displacement (D) is the shortest distance from the initial to the final position.
In this example distance is 5 km north - 2 km south = 3 km north (look at the image).

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We know that whatever amount we start with, half of it decays and forms atoms of other elements in 175 hours.  So in order to figure out how much is left after 525 hours, we'll need to know how many half-lifes pass in that amount of time.

Well, (525 divided by 175) is exactly 3 half-lifes.  So this will be easy.

-- After 1 half-life . . .

. . . . . 50% decays, 50% is still there.

-- After the 2nd half-life . . .

. . . . . (half of the leftover 50%) = another 25% decays, 25% is left.

-- After the 3rd half-life . . .

. . . . . (half of the leftover 25%) = another 12.5% decays, 12.5% is left.

12.5% of 4,000g = (0.125 x 4,000g) = <em>500 g</em> .

============================================

<u>Another way</u>:

After 1 half-life, 1/2 is left.

After 2 half-lifes, 1/4 is left.

After 3 half-lifes, 1/8 is left.

1/8 of 4,000g = (4,000g/8) = <em>500 g </em>.

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c. low beams and fog lights

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8 0
3 years ago
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madam [21]

Hi there!

We can use the kinematic equation:

v_f^2 = v_i^2 + 2ad

vf = Final velocity (? m/s)

vi = initial velocity (0 m/s, dropped from rest)

a = acceleration (due to gravity, 9.8 m/s²)

d = distance (9.8 m)

Simplify the equation to solve for vf:

v_f^2 = 0 + 2ad\\\\v_f = \sqrt{2ad}

Substitute in the given values:

v_f = \sqrt{2(9.8)(9.8)} = \boxed{13.86 m/s}

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sp2606 [1]

Answer:

7.9m/s

Explanation:

We are given that

Mass of wagon=40 kg

\theta=18.5^{\circ}

Tension=140 N

Initial velocity of wagon=u=0

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Net force applied  on wagon=F=T-mgsin\theta=140-40(9.8)sin18.5=15.7 N

By using g=9.8m/s^2

a=\frac{F}{a}=\frac{15.7}{40}=0.39m/s^2

We know that

v^2-u^2=2as

Using the formula

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v=\sqrt{2\times 0.39\times 80}=7.9m/s

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3 years ago
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