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levacccp [35]
3 years ago
15

If a^2 -b^2 =12 and a-b=4 what is the bay of a +b

Mathematics
1 answer:
slava [35]3 years ago
7 0

Answer:

a+b = 3

Step-by-step explanation:

a = b+4

a^2 = (b+4)(b+4) = b^2 + 8b +16=-b^2 = 12

8b=-4

b = - 1/2

a = 3.5

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The balloon ascended 1300ft.

WORK:

3*60=180

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3 years ago
Given f(x) = 2x + 9, if f(x) = 15, find x.​
AleksandrR [38]

Answer:

<h2>x = 3</h2>

Step-by-step explanation:

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The first two terms in an arithmetic progression are -2 and 5. The last term in the progression is the only number in the progre
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Given:

The first two terms in an arithmetic progression are -2 and 5.

The last term in the progression is the only number in the progression that is greater than 200.

To find:

The sum of all the terms in the progression.

Solution:

We have,

First term : a=-2

Common difference : d = 5 - (-2)

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nth term of an A.P. is

a_n=a+(n-1)d

where, a is first term and d is common difference.

a_n=-2+(n-1)(7)

According to the equation, a_n>200.

-2+(n-1)(7)>200

(n-1)(7)>200+2

(n-1)(7)>202

Divide both sides by 7.

(n-1)>28.857

Add 1 on both sides.

n>29.857

So, least possible integer value is 30. It means, A.P. has 30 term.

Sum of n terms of an A.P. is

S_n=\dfrac{n}{2}[2a+(n-1)d]

Substituting n=30, a=-2 and d=7, we get

S_{30}=\dfrac{30}{2}[2(-2)+(30-1)7]

S_{30}=15[-4+(29)7]

S_{30}=15[-4+203]

S_{30}=15(199)

S_{30}=2985

Therefore, the sum of all the terms in the progression is 2985.

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