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3 years ago

At which position is the kinetic energy of a particle executing SHM greatest?

Physics

1 answer:

Over [174]3 years ago

8 0

Explanation:

The kinetic energy of a particle in SHM is given by :

$K=\dfrac{1}{2}m\omega^2(A^2-x^2)$

Where

m is the mass of a particle

A is the amplitude

x is the distance

$\omega$ is the angular frequency

The kinetic energy of a particle executing SHM is maximum at its equilibrium position and minimum at a maximum displacement from the equilibrium point.

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Usimov [2.4K]

Answer:

Explanation:

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4 years ago

The speed of surface waves in water decreases as the water becomes shallower. Suppose waves travel across the surface of a lake

Elanso [62]

Answer:

The correct solution is "1.2 m".

Explanation:

The given values are:

Wavelength of waves,

λ = 1.5 m

Speed of waves on surface,

V = 2 m/sec

Speed of waves in water,

V₁ = 1.6 m/sec

As we know,

⇒ $V=f\times \lambda$

or,

⇒ $f=\frac{V}{\lambda}$

On substituting the values, we get

⇒ $=\frac{2}{1.5}$

⇒ $=1.33 \ Hz$

hence,

⇒ $\lambda_1=\frac{V_1}{f}$

On substituting the values, we get

⇒ $=\frac{1.6}{1.33}$

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7 0

3 years ago

N capacitors are connected in parallel to form a "capacitor circuit". The capacitance of first capacitor is C, second one is C/2

liberstina [14]

Answer:

Explanation:

The equivalent capacitance of a parallel combination of capacitors is the sum of their capacitance.

So, if the capacitance of each capacitor is half the previous one, we have a geometric series with first term = C and rate = 0.5.

Using the formula for the sum of the infinite terms of a geometric series, we have:

Sum = First term / (1 - rate)

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So the equivalent capacitance of this parallel connection is 2C.

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4 years ago

two projectiles are fired at equal speeds but differentangles. one is fired at an angle of 30 degrees and the other at 60degrees

zheka24 [161]

Answer:

a) 30 degree

Explanation:

As we know that time of flight of the projectile depends on the the vertical component of the velocity always

It is given as

$T = \frac{2v_y}{g}$

now we know that

$v_y = vsin\theta$

so we will have

$T = \frac{2vsin\theta}{g}$

since we know that two projectiles are projected at same speed but different angles

so smaller the angle will take smaller time

so it would be 30 degree projectile which will take smaller time

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3 years ago

Solving equation for the quantity indicated

Slav-nsk [51]

T = (vf -vo)/a. .......

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3 years ago

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