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3 years ago

At which position is the kinetic energy of a particle executing SHM greatest?

Physics

1 answer:

Over [174]3 years ago

8 0

Explanation:

The kinetic energy of a particle in SHM is given by :

$K=\dfrac{1}{2}m\omega^2(A^2-x^2)$

Where

m is the mass of a particle

A is the amplitude

x is the distance

$\omega$ is the angular frequency

The kinetic energy of a particle executing SHM is maximum at its equilibrium position and minimum at a maximum displacement from the equilibrium point.

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PLZZZZZ ANSWER Which example describes a nonrenewable resource?

Zepler [3.9K]

Answer:

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Explanation:

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So, the answer is D.

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3 years ago

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Answer:

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Explain how a clinical thermometer should be sterilized and why

Kisachek [45]

Answer:

Explain why it is not advisable to sterilise a clinical thermometer on boiling water at normal atmospheric temperature. A clinical thermometer has small temperature range. The glass will crack/burst due to excessive pressure created by expansion of mercury.

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2 years ago

Chromatic aberration comes from the fact that different wavelengths of light travel at different speeds through the material of

gtnhenbr [62]

Answer:

y_red / y_blue = 1.11

Explanation:

Let's use the constructor equation to find the image for each wavelength

1 /f = 1 /o + 1 /i

Where f is the focal length, or the distance to the object and i the distance to the image

Red light

1 / i = 1 / f - 1 / o

1 / i_red = 1 / f_red - 1 / o

1 / i_red = 1 / 19.57 - 1/30

1 / i_red = 1,776 10-2

i_red = 56.29 cm

Blue light

1 / i_blue = 1 / f_blue - 1 / o

1 / i_blue = 1 / 18.87 - 1/30

1 / i_blue = 1,966 10-2

i_blue = 50.863 cm

Now let's use the magnification ratio

m = y ’/ h = - i / o

y ’= - h i / o

Red Light

y_red ’= - 5 56.29 / 30

y_red ’= - 9.3816 cm

Light blue

y_blue ’= 5 50,863 / 30

y_blue ’= - 8.47716 cm

The ratio of the height of the two images is

y_red ’/ y_blue’ = 9.3816 / 8.47716

y_red / y_blue = 1,107

y_red / y_blue = 1.11

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3 years ago

a 75 kg man is standing at rest on ice while holding a 4kg ball. if the man throws the ball at a velocity of 3.50 m/s forward, w

AysviL [449]

Answer:

His resulting velocity will be 0.187 m/s backwards.

Explanation:

Given:

Mass of the man is, $M=75\ kg$

Mass of the ball is, $m=4\ kg$

Initial velocity of the man is, $u_m=0\ m/s(rest)$

Initial velocity of the ball is, $u_b=0\ m/s(rest)$

Final velocity of the ball is, $v_b=3.50\ m/s$

Final velocity of the man is, $v_m=?\ m/s$

In order to solve this problem, we apply law of conservation of momentum.

It states that sum of initial momentum is equal to the sum of final momentum.

Momentum is the product of mass and velocity.

Initial momentum = Initial momentum of man and ball

Initial momentum = $Mu_m+mu_b=75\times 0+4\times 0 =0\ Nm$

Final momentum = Final momentum of man and ball

Final momentum = $Mv_m+mv_b=75\times v_m+4\times 3.50 =75v_m+14$

Now, initial momentum = final momentum

$0=75v_m+14\\\\75v_m=-14\\\\v_m=\frac{-14}{75}\\\\v_m=-0.187\ m/s$

The negative sign implies backward motion of the man.

Therefore, his resulting velocity is 0.187 m/s backwards.

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3 years ago