Question

At which position is the kinetic energy of a particle executing SHM greatest?

Answer 1

Explanation:

The kinetic energy of a particle in SHM is given by :

$K=\dfrac{1}{2}m\omega^2(A^2-x^2)$

Where

m is the mass of a particle

A is the amplitude

x is the distance

$\omega$ is the angular frequency

The kinetic energy of a particle executing SHM is maximum at its equilibrium position and minimum at a maximum displacement from the equilibrium point.