Answer:
The velocity of the ball when it first hit the net is Vi= 106.97 m/s
Explanation:
Vf= 0
Vi= ?
a= 56.3 m/s²
t= 1.9 s
Vf= Vi - a*t
Vi= a*t
Vi= 106.97 m/s
A descriptive observation may very well be a mixture of both quantitative and qualitative as it can utilize elements of both types. Qualitative deals with the kinds of observations that cannot be measured in numerical form. Quantitative data is just that.
Answer:
Weight=686.7N,
, S.G.=0.933, F=17.5N
Explanation:
So, the first value the problem is asking us for is the weight of methanol. (This is supposing there is a mass of methanol of 70kg inside the tank). We can find this by using the formula:
W=mg
so we can substitute the data the problem provided us with to get:

which yields:
W=686.7N
Next, we need to find the density of methanol, which can be found by using the following formula:

we know the volume of methanol is 75L, so we can convert that to
like this:

so we can now use the density formula to find our the methanol's density, so we get:



Next, we can us these values to find the specific gravity of methanol by using the formula:

when substituting the known values we get:

so:
S.G.=0.933
We can now find the force it takes to accelerate this tank linearly at 
F=ma

F=17.5N
Answer:
α = 1215.71 rad/s²
Explanation:
The angular acceleration of an object is defined as the time rate of change of angular velocity of he object. The formula for the angular acceleration of an object is given as follows:
α = (ωf - ωi)/Δt
where,
α = angular acceleration of the disk = ?
ωf = Final Angular Velocity = 0 rad/s (Since disk finally stops)
ωi = Initial Angular Velocity = (5050 rpm)(2π rad/rev)(1 min/60 s)
ωi = 528.83 rad/s
Δt = time interval = 0.435 s
Therefore,
α = (0 rad/s - 528.83 rad/s)/(0.435 s)
α = - 1215.71 rad/s²
here, negative sign indicates that the direction of acceleration is opposite to the direction of angular velocity or the angular motion. So, the magnitude of acceleration will be:
<u>α = 1215.71 rad/s²</u>