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Zigmanuir [339]
2 years ago
6

Write the acid-base reaction that occurs when an aqueous solution of HCl is added to an aqueous solution of NaOH. (Use the lowes

t possible coefficients. Omit states-of-matter in your answer.)
For Data Table B, the pH of baking soda (sodium bicarbonate) was measured. Answer the following questions based on your observations. (Use the lowest possible coefficients. Include states-of-matter under the given conditions in your answer.)
(a) Write the dissolution reaction for solid sodium bicarbonate below.
Once the ionic solid has dissolved, theamphiproticanion that is formed is able to react as an acid or as a base with water. (For questions b and c, omit states-of-matter in your answer.)
(b) Write the acid-base reaction where hydrogen carbonate is the acid and water is the base.
(c) Write the acid-base reaction where water is the acid and hydrogen carbonate is the base.
Chemistry
2 answers:
Sloan [31]2 years ago
4 0
H3O+(aq) + OH-(aq) --> 2H2O (l)

NaHCO3(s) --> NaH 2+ (aq) + CO3 2- (aq)

NaH 2+ (aq) + H2O (l) --> Na+ (aq) + H3O+ (aq)

H2O (l) + CO3 2- (aq) --> OH- (aq) + HCO3- (aq)

(I'm not completely sure if I did the third question right) I'm sorry if I got it wrong
Pepsi [2]2 years ago
3 0

<u>Answer:</u> The chemical equations are written below.

<u>Explantaion:</u>

An acid-base reaction is known as neutralization reaction.

Neutralization reaction is defined as the reaction in which an acid reacts with a base to produce a salt and water molecule.

The chemical equation for the reaction of HCl and NaOH follows:

HCl+NaOH\rightarrow NaCl+H_2O

By Stoichiometry of the reaction:

1 mole of HCl reacts with 1 mole of NaOH to produce 1 mole of sodium chloride and 1 mole of water molecule.

  • <u>For a:</u>

The chemical equation for the dissolution of solid sodium bicarbonate in water follows:

NaHCO_3(s)+H_2O(l)\rightarrow Na^+(aq.)+HCO_3^-(aq.)

By Stoichiomtery of the reaction:

1 mole of solid sodium bicarbonate reacts with 1 mole of water, to produce 1 mole of aqueous solution of sodium ions and 1 mole of aqueous solution of hydrogen carbonate ions.

  • <u>For b:</u>

An acid is a substance which looses hydrogen ion when dissolved in water and a base is defined as the substance which accepts hydrogen ion.

The chemical equation where hydrogen carbonate is an acid and reacts with water follows:

HCO_3^-+H_2O\rightarrow CO_3^{2-}+H_3O^+

By Stoichiometry of the reaction:

1 mole of hydrogen carbonate ion reacts with water to produce carbonate ions and hydronium ions.

  • <u>For c:</u>

The chemical equation where hydrogen carbonate is an base and reacts with water follows:

HCO_3^-+H_2O\rightarrow H_2CO_3+OH^-

By Stoichiometry of the reaction:

1 mole of hydrogen carbonate ion reacts with water to produce carbonic acid and hydroxide kions.

Hence, the chemical equations are written above.

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The balanced chemical equation between iron and oxygen to produce iron (III) oxide is,

4Fe(s) + 3O_{2}(g) ---> 2Fe_{2}O_{3}(s)

Mass of Fe = 227.8 g

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Mass of oxygen = 128 g

Moles of O_{2} = 128 g O_{2}*\frac{1 mol O_{2}}{32 g O_{2}}= 4mol O_{2}

Calculating the limiting reactant: The reactant that produces the least amount of product will be the limiting reactant.

Mass of iron (III) oxide produced from Iron = 4.079 mol Fe * \frac{2 mol Fe_{2}O_{3}}{4 mol Fe}  *\frac{159.69 g Fe_{2}O_{3}}{1 mol Fe_{2}O_{3}} = 325.7 g Fe_{2}O_{3}

Mass of iron (III) oxide produced from oxygen=4 mol O_{2}*\frac{2 molFe_{2}O_{3}}{3 mol O_{2}}*\frac{159.69 g Fe_{2}O_{3}}{1 mol Fe_{2}O_{3}} =  425.84 g Fe_{2}O_{3}

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C3H8(g) + 5O2(g) ⟶ 3CO2(g) + 4H2O(g) H = -2220 kJ If 865.9 g of H2O is produced during this combustion, how much heat is generat
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3 × 10⁴ kJ

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Step 2: Calculate the moles corresponding to 865.9 g of H₂O

The molar mass of H₂O is 18.02 g/mol.

865.9 g × 1 mol/18.02 g = 48.05 mol

Step 3: Calculate the heat produced when 48.05 moles of H₂O are produced

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