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galina1969 [7]
3 years ago
10

HELP PLEASE. STRUGGLING. Which of the following is true in an acidic solution? A)The molarity of hydroxide is double the molarit

y of hydronium. B)The molarity of hydroxide is equal to the molarity of hydronium. C)The molarity of hydroxide is lower than the molarity of hydronium. D)The molarity of hydroxide is higher than the molarity of hydronium.
Chemistry
1 answer:
fredd [130]3 years ago
3 0
The statement that would be held true for an acidic solution would be option C. The molarity or concentration of the hydronium ions would be more than that of the hydroxide ions. As the acidity of a solution increases as there is a greater amount of H+ or H3O+ ions present, within it. This is will give us a low pH and thus is quite acidic.

If the concentrations of the OH- and H3O+ are the same then the solution would be neutral, and if the opposite is true. The concentration of OH- is more than H3O+ than the solution would be basic.
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A- is a weak base. which equilibrium corresponds to the equilibrium constant ka for ha?
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K_a=\frac{[H^+][A^-]}{[HA]}

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Consider the following reaction:
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1. d[H₂O₂]/dt = -6.6 × 10⁻³ mol·L⁻¹s⁻¹; d[H₂O]/dt = 6.6 × 10⁻³ mol·L⁻¹s⁻¹

2. 0.58 mol

Explanation:

1.Given ΔO₂/Δt…

    2H₂O₂     ⟶      2H₂O     +     O₂

-½d[H₂O₂]/dt = +½d[H₂O]/dt = d[O₂]/dt  

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 d[H₂O]/dt =  2d[O₂]/dt =  2 × 3.3 × 10⁻³ mol·L⁻¹s⁻¹ =  6.6 × 10⁻³mol·L⁻¹s⁻¹

2. Moles of O₂  

(a) Initial moles of H₂O₂

\text{Moles} = \text{1.5 L} \times \dfrac{\text{1.0 mol}}{\text{1 L}} = \text{1.5 mol }

(b) Final moles of H₂O₂

The concentration of H₂O₂ has dropped to 0.22 mol·L⁻¹.

\text{Moles} = \text{1.5 L} \times \dfrac{\text{0.22 mol}}{\text{1 L}} = \text{0.33 mol }

(c) Moles of H₂O₂ reacted

Moles reacted = 1.5 mol - 0.33 mol = 1.17 mol

(d) Moles of O₂ formed

\text{Moles of O}_{2} = \text{1.33 mol H$_{2}$O}_{2} \times \dfrac{\text{1 mol O}_{2}}{\text{2 mol H$_{2}$O}_{2}} = \textbf{0.58 mol O}_{2}\\\\\text{The amount of oxygen formed is $\large \boxed{\textbf{0.58 mol}}$}

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