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galina1969 [7]
3 years ago
10

HELP PLEASE. STRUGGLING. Which of the following is true in an acidic solution? A)The molarity of hydroxide is double the molarit

y of hydronium. B)The molarity of hydroxide is equal to the molarity of hydronium. C)The molarity of hydroxide is lower than the molarity of hydronium. D)The molarity of hydroxide is higher than the molarity of hydronium.
Chemistry
1 answer:
fredd [130]3 years ago
3 0
The statement that would be held true for an acidic solution would be option C. The molarity or concentration of the hydronium ions would be more than that of the hydroxide ions. As the acidity of a solution increases as there is a greater amount of H+ or H3O+ ions present, within it. This is will give us a low pH and thus is quite acidic.

If the concentrations of the OH- and H3O+ are the same then the solution would be neutral, and if the opposite is true. The concentration of OH- is more than H3O+ than the solution would be basic.
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Can a element be a metal and a non metal
Dmitry [639]

Answer:

no

Explanation:

because in the periodic table there is a section for metals and a section for non metals. 'non' implies that it is not a metal and having an element be both metal and non metal would be contradictory.

6 0
3 years ago
There are ______ electrons, _______ protons, and ______ neutrons in an atom of .
Georgia [21]

There are 54 electrons, 54 protons, and 78 neutrons in an atom of 132 Xe.54.

Xenon is a chemical element with the symbol Xe and atomic number 54. It is a colourless, dense, odourless noble gas found in Earth's atmosphere in trace amounts.

Although generally unreactive, it can undergo a few chemical reactions such as the formation of xenon hexafluoroplatinate, the first noble gas compound to be synthesized.

Solid xenon changes from face-centred cubic (fcc) to hexagonal close packed (hcp) crystal phase under pressure and begins to turn metallic at about 140 GPa, with no noticeable volume change in the hcp phase. It is completely metallic at 155 GPa.

When metallized, xenon appears sky blue because it absorbs red light and transmits other visible frequencies. Such behaviour is unusual for a metal and is explained by the relatively small width of the electron bands in that state.

Full question :

Q. There are ________ electrons,_______ protons, and ______ neutrons in an atom of 132 Xe.54.

a) 78 78 132

b) 54 54 78

c) 54 54 132

d) 78 78 54

e)132 132 54

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7 0
2 years ago
What can create sediment
bearhunter [10]
Sediment is created by wind and water.

4 0
4 years ago
Read 2 more answers
Assume that the complete combustion of one mole of glucose, a monosaccharide, to carbon dioxide and water liberates 2870 kJ2870
Lubov Fominskaja [6]

Answer:

number of moles of the compound \approx 53 mole

Explanation:

Given that:

The total energy liberated = - 2870 kJ  ( here , the negative sign typical implies the release of energy due to the combustion reaction)

The equation of the reaction can be represented as:

\mathbf{C_6H_{12}O_6_{(s)} + 6O_{2(g)} \to 6CO_{2(g)}+6H_2O_{(l)}}

The energy needed to synthesize 1 mole of compound X  = - 54.1 kJ.mol

Thus;

The total energy = numbers of moles of compound × Energy needed to synthesize  1 mole of compound X

Making the numbers of moles of the compound the subject; we have;

numbers of moles of compound = numbers  \ of \  moles  \ of \  compound =  \dfrac{total \ energy }{Energy \  needed  \ to  \ synthesize \   1  \ mole \  of \  compound  \ X}numbers  \ of \  moles  \ of \  compound =  \dfrac{-2870  \ kJ }{-54.1  \ kJ/mol}

number of moles of the compound = 53.04990  mole

number of moles of the compound \approx 53 mole to two significant figure

7 0
3 years ago
How many liters of 1.0 M HCl do you need to neutralize 2.0 L of 3.0 M NaOH? How many liters of 1.0 M HCl do you need to neutrali
Kruka [31]

<u>Answer: </u>

<u>For 1:</u> The volume of HCl required is 6 L.

<u>For 2:</u> The volume of HCl required is 9 L.

<u>For 3:</u> The volume of sulfuric acid required is 4.5 L.

<u>Explanation:</u>

To calculate the volume of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2        ......(1)

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base

  • <u>For 1:</u>

We are given:

n_1=1\\M_1=1M\\V_1=?L\\n_2=1\\M_2=3.0M\\V_2=2.0L

Putting values in equation 1, we get:

1\times 1\times V_1=1\times 3\times 2\\\\V_1=6L

Hence, the volume of HCl required is 6 L.

  • <u>For 2:</u>

We are given:

n_1=1\\M_1=1M\\V_1=?L\\n_2=2\\M_2=3.0M\\V_2=1.5L

Putting values in equation 1, we get:

1\times 1\times V_1=2\times 3.0\times 1.5\\\\V_1=9L

Hence, the volume of HCl required is 9 L.

  • <u>For 3:</u>

To calculate the volume of acid, we use the equation:

N_1V_1=N_2V_2

where,

N_1\text{ and }V_1 are the normality and volume of acid

N_2\text{ and }V_2 are the normality and volume of base

We are given:

N_1=1.0N\\V_1=?L\\N_2=3.0N\\V_2=1.5L

Putting values in above equation, we get:

1.0\times V_1=3.0\times 1.5\\\\V_1=4.5L

Hence, the volume of sulfuric acid required is 4.5 L.

8 0
3 years ago
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