Answer:
The volume of NH₃ produced is 3.6 L
Explanation:
Let's make the reaction:
N₂ (g) + 3H₂ (g) ⇄ 2NH₃ (g)
We have the volume of H₂ which has reacted, but we don't have the mass (neither the moles). We must apply density of H₂ to know this data:
δH₂ (g) = 0.071 g/l
density = mass / volume
0.071 g/L = mass / 6.52L
0.071 g/L . 6.52L = mass → 0.463 g
Molar mass of H₂ = 2 g/m
Mass / Molar mass = moles
0.463 g /2g/m = 0.231 moles
In the reaction ratio between hydrogen and ammonia is 3:2
3 moles of H₂ _____ 2 moles of ammonia
0.231 moles H₂ ____ (0.231 .2)/3 = 0.154 moles
These are the moles of ammonia which are produced, so we have to convert this to mass, to apply NH₃ 's density.
moles . molar mass = mass
Molar mass NH₃ = 17 g/m
0.154 m . 17g/m = 2.62 g
NH₃ density = 0,00073 g/ml
NH₃ density = NH₃ mass / NH₃ volume
NH₃ volume = NH₃ mass / NH₃ density
NH₃ volume = 2.62 g /0,00073 g/ml
NH₃ volume = 3593.4 mL
3593.4 mL /1000 ≅ 3.6L
