<u>Answer</u>
The combined displacement is 2km north
<u>Explanation</u>
Since displacement is a vector quantity, we take into account the direction.
Good for us all the displacement vectors are in the same dimension, so we can make north positive and south negative or vice-versa.
We now add to obtain,

This will simplify to

Therefore the combined displacement is 2km north
Answer:
38.87 m/s
Explanation:
Given that the ball is dropped from a height = 77 m
u = 0 m/s
s = 77 m
a = g = 9.81 m/s²
Applying the expression as:

Applying values as:

<u>The speed with which the ball hit the ground = 38.87 m/s</u>
Answer:
26.5 m
Explanation:
= initial position of the object = 75.2 m
= final position of the object
= displacement of the object = - 48.7
Displacement of the object is given as the difference of final and initial position of the object

Inserting the values
- 48.7 = x - 75.2
x = 26.5 m
To solve this problem it is necessary to apply the equations given from Bernoulli's principle, which describes the behavior of a liquid moving along a streamline. Mathematically this expression can be given as,

Where,
Pressure at each state
= Density
Velocity
Re-organizing the expression we can get that

Our values are given as


Normal Conditions
Replacing we have,


If we consider that there is a balance between the two states, the Force provided by gravity is equivalent to the Support Force, therefore

Here the lift force is the product between the pressure difference previously found by the effective area of the aircraft, while the Force of gravity represents the weight. There,


Equating,



Therefore the weight of the plane is 14535N