Why does a satellite in a circular orbit travel at a constant speed? why does a satellite in a circular orbit travel at a constant speed? there is a force acting opposite to the direction of the motion of the satellite. there is no component of force acting along the direction of motion of the satellite. the net force acting on the satellite is zero. the gravitational force acting on the satellite is balanced by the centrifugal force acting on the satellite?
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E) Protons, neutrons, and electrons
Answer:
<em><u>A binary star is a star system consisting of two stars orbiting around their common barycenter. </u></em>
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<span>If you are looking to get an object up the highest, shoot it straight up. If you want to go for a specific horizontal displacement, use the range equation. R = v2sin(twice the launch angle)/ g. g is the gravitaional constant, 9.8 meters per second. Use degrees for the angle. v is the launch velocity. R is the horizontal displacement. This formula only works if your start altitude and end altitude are the same, i.e. you must shoot over a level field.
it depends on the gravitational force of attraction of earth and air resistance.
if we are neglecting air resistance, the max.horizontal distance is according to this formulae,
V0/2 * sin (2theta)
where V0 is the initial velocity
theta is the angle with x axis and the projection.
There are a number of ways that you could find a horizontally displaced object. You could for example just look.</span>
