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2 years ago

Which of the following is NOT a way to identify a mineral

Physics

1 answer:

arsen [322]2 years ago

6 0

Answer:

Color, however, is the least useful property for mineral identification. One reason is that many minerals have similar colors. Also, impurities can turn colorless minerals into colored minerals.

Explanation:

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Calculate the tension on the rope.<br> A. 57.89 N<br> B. 32.73 N<br> C. 69.84 N<br> D. 12.55 N

Ratling [72]

Hi there!

$\large\boxed{\text{B. 32.73N}}$

To calculate the tension, we must calculate the acceleration of the system.

Begin with a summation of forces:

∑F = -M₁gsinФ + T - T + M₂g

Simplify and solve for acceleration: (Tensions cancel out)

$a = \frac{-M_1gsin\theta + T - T + M_2g}{M_1+M_2}$

Plug in values. Let g = 10 m/s²

$a = \frac{-3(10)(sin30)+8(10)}{3+8} = 5.91 m/s^{2}$

Now, to find tension, let's sum up the forces acting on ONE block. For simplicity, we can look at the hanging block:

∑F = -T + W

ma = -T + W

Rearrange to solve for T:

T = W - ma

We know the acceleration, so plug in the values:

T = (8)(10) - (8)(5.91) = 32.73 N

3 0

3 years ago

A ____________ is the measure of how far the particles in the medium move away from their normal rest position.

Bezzdna [24]

Explanation:

Amplitude is your answer..

Mate..

hope you like it

5 0

3 years ago

What is the definition of light of one year ?

Elodia [21]

Answer:

The definition of a light year is the distance a photon will travel in a year in a vaccume, like space.

8 0

3 years ago

Read 2 more answers

A solid ball with a mass of 3.56 kg and a radius of 0.094 m starts from rest at the top of a 86.4 â¦ slope with a vertical heigh

PtichkaEL [24]

Let: m=1.50Kg, r=0.094m, h=2.50m, teta=86.4 and g=9.81m/s^2. The moment of inertia of a sphere is I=(2/5)*m*r^2, vi=0m/s, hf=0m, and the condition that a spherical object is rolling whitout slipping is w=V/r. So, by conservation of energy: mgh= (1/2)*((m*Vf^2)+(I*wf)). substituting, and clearing, Vf=((10/7)*g*h)^(1/2)=((10/7)*(9.81)*(2.50))^(1/2)=5.9190 m/s

8 0

3 years ago

The work function of a metal surface is 4.80 × 10-19 J. The maximum speed of the electrons emitted from the surface is vA = 7.7

poizon [28]

Answer:

$\lambda_A=2.65177\times 10^{-7}\ m$

$\lambda_B=3.32344\times 10^{-7}\ m$

Explanation:

h = Planck's constant = $6.63\times 10^{-34}\ m^2kg/s$

c = Speed of light = $3\times 10^8\ m/s$

m = Mass of electron = $9.11\times 10^{-31}\ kg$

$W_0$ = Work function = $4.8\times 10^{-19}\ J$

$v_A$ = Velocity of A particle = $7.7\times 10^5\ m/s$

$v_B$ = Velocity of B particle = $5.1\times 10^5\ m/s$

The wavelength is given by

$\lambda=\frac{hc}{\frac{1}{2}mv^2+W_0}$

$\lambda_A=\frac{6.63\times 10^{-34}\times 3\times 10^8}{\frac{1}{2}9.11\times 10^{-31}(7.7\times 10^5)^2+4.8\times 10^{-19}}\\\Rightarrow \lambda_A=2.65177\times 10^{-7}\ m$

The wavelength $\lambda_A=2.65177\times 10^{-7}\ m$

$\lambda_B=\frac{6.63\times 10^{-34}\times 3\times 10^8}{\frac{1}{2}9.11\times 10^{-31}(5.1\times 10^5)^2+4.8\times 10^{-19}}\\\Rightarrow \lambda_B=3.32344\times 10^{-7}\ m$

The wavelength $\lambda_B=3.32344\times 10^{-7}\ m$

5 0

3 years ago