Answer:
A physical property is an aspect of matter that can be observed or measured without changing it. A chemical property may only be observed by changing the chemical identity of a substance.
Explanation:
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When gases get cooler the molecules slow down or lose energy and condense so the volume in the tire or soccer ball would decrease and may feel flatter
The Rutherford experiment proved the Thomson “plum-pudding” model of the atom to be essentially correct did not give the results described and is denoted as option A.
<h3>What is Thomson “plum-pudding” model?</h3>
This model was proposed by J.J Thomson in which referred an atom as a sphere of positive charge, and negatively charged electrons are embedded in it to balance the total positive charge.
This model was incorrect and the Rutherford atomic model was adopted in which he described the electrons orbits about a tiny positive nucleus.
The nucleus contains protons and neutrons instead thereby making it the correct choice.
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The options include the following:
a.The Rutherford experiment proved the Thomson “plum-pudding” model of the atom to be essentially correct.
b.The Rutherford experiment was useful in determining the nuclear charge on the atom.
c.Milikan’s oil-drop experiment showed that the charge on any particle was a simple multiple of the charge on the electron.
d.The electric discharge tube proved that electrons have a negative charge
Answer:
92.49 %
Explanation:
We first calculate the number of moles n of AgBr in 0.7127 g
n = m/M where M = molar mass of AgBr = 187.77 g/mol and m = mass of AgBr formed = 0.7127 g
n = m/M = 0.7127g/187.77 g/mol = 0.0038 mol
Since 1 mol of Bromide ion Br⁻ forms 1 mol AgBr, number of moles of Br⁻ formed = 0.0038 mol and
From n = m/M
m = nM . Where m = mass of Bromide ion precipitate and M = Molar mass of Bromine = 79.904 g/mol
m = 0.0038 mol × 79.904 g/mol = 0.3036 g
% Br in compound = m₁/m₂ × 100%
m₁ = mass of Br in compound = m = 0.3036 g (Since the same amount of Br in the compound is the same amount in the precipitate.)
m₂ = mass of compound = 0.3283 g
% Br in compound = m₁/m₂ × 100% = 0.3036/0.3283 × 100% = 0.9249 × 100% = 92.49 %
Answer:
Depth and location affect ocean water’s temperature.
Explanation:
The main source of heat for the oceans is solar radiation. That is, water is basically heated by the radiation of the Sun, which transmits energy to the surface. The ocean absorbs this energy and stores it. Seawater has high caloric capacity. This means that more energy and more time is needed to change or increase the water temperature, compared to the air temperature. Similarly, once the ocean heats up, it takes a long time for the water to completely release or lose that heat.
The temperature decreases to greater depth, because the amount of solar radiation is reduced. On the contrary, it is greater where there is greater energy or heat content.
The closer a place is to the equator, the solar energy will affect more vertically and with more intensity on it, so the warmer the temperatures will be. The further that point of the equator is found, the solar energy will reach it with a smaller angle. And if the point is near the poles, the sun's rays will arrive at a very small angle. This causes the temperature of the water of the oceans to vary depending on the earth's latitude, being higher in areas close to the equator and the tropics, and colder the closer to the poles or the further away from the temperate zones.
