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kakasveta [241]
3 years ago
10

What is the mass, in grams, of

Chemistry
1 answer:
DIA [1.3K]3 years ago
4 0

Answer:

The answers to your question are below

Explanation:

a) 6.85×1020 H2O2 molecules

H2O2   MW = 32 + 2 = 34 g

                                    34g -------------------- 6.023 x 10²³ molecules

                                    x       -------------------  6.85 x 10 ²⁰

                                   x = (6.85 x 10 ²⁰)(34)/  6.023 x 10²³

                                   x = 0.038 g

3.3×1022 SO2 molecules

MW SO2 = 32 + 32 = 64g

                                    64 g -------------------- 6.023 x 10²³ molecules

                                    x      --------------------  3.3×1022 SO2 molecules

                                    x = (3.3×1022 SO2)(64) / 6.023 x 10²³

                                   x = 3.51 g

5.5×1025 O3 molecules

MW = 16 x 3 = 48g

                                 48 g -----------------   6.023 x 10²³ molecules

                                  x     ------------------   5.5×1025 O3 molecules

                               x = (5.5×1025 )(48) /  6.023 x 10²³

                               x = 4383 g

9.30×1019 CH4 molecules

MW = 12 + 4 = 16 g

                              16 g --------------------  6.023 x 10²³ molecules

                              x      --------------------   9.30×1019 CH4 molecules

                           x = (9.30×1019)(16) / 6.023 x 10²³

                           x = 0.0025 g

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denpristay [2]

Balance the equation first: 

2 Fe+6 HNO3→2 Fe(NO3)3+3H2

Then calculate mass of Iron :

4.5×3.0×3.5 cm3(1 mL1 cm3)(7.87 g Fe1 ml)=371.86 g Fe

Now use Stoichiometry:

371.86 g Fe×(1 mol Fe55.85 g Fe)×(6 mol HNO32 mol Fe)=19.97 mol HNO3

Convert moles of nitric acid to grams

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7 0
3 years ago
Read 2 more answers
Here's the question ~
Lelechka [254]

Using the Rydberg formula, the spectral line of H - atom is suitable for this purpose is Paschen, ∞ → 3.

  • Using the Rydberg formula;

1/λ = RH(1/nf^2 - 1/ni^2)

Given that;

λ = wavelength

RH = Rydberg constant

nf = final state

ni = initial state

  • When final state = 3 and initial state = ∞

Then;

1/λ =  1 × 10^7 m-1 (1/3^2 - 1/ ∞^2)

1/λ =  1 × 10^7 m-1 (1/3^2 )

λ = 900 nm

Hence, the correct answer is Paschen, ∞ → 3

Learn more about the Rydberg formula; brainly.com/question/17753747

3 0
2 years ago
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The shielding of electrons gives rise to an effective nuclear charge, Zeff, which explains why boron is larger than oxygen. Esti
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Zeff = Z - S

Here, Z is the number of protons in the nucleus, that is, atomic number, and S is the number of nonvalence electrons.

For boron, the electronic configuration is 1s₂ 2s₂ 2p₄

Z = 5, S = 2

Zeff = 5-2 = +3

For O, electronic configuration is 1s₂ 2s₂ 2p₄

Z = 8, S = 2

Zeff = 8-2 = +6

Hence, the correct answer is second option, that is, +3 and +6, the Zeff of boron is smaller in comparison to O, thus, boron exhibits a bigger size than O.

3 0
3 years ago
How would you separate a mixture of 4-tert-butylphenol and 2- chlorobenzoic acid? Explain the detailed steps including the choic
Sergeu [11.5K]

The a mixture of 4-tert-butylphenol and 2- chlorobenzoic acid is separate by the by using  bicarbonate solvent.

When solution of bicarbonate is added in mixture of 4-tert-butylphenol and 2- chlorobenzoic acid then 2- chlorobenzoic acid form a carboxylate ion whereas 4-tert-butylphenol  is underacted and filtered out.

Since, only 2- chlorobenzoic acid which is acid is convert into its conjugate base by solution of bicarbonate in mixture of 4-tert-butylphenol and 2- chlorobenzoic acid .

However, phenol is less acidic than carboxylic acid. Both phenol and carboxylic acid is soluble in organic solvent . At that point as the phenol isolates as an oil, one needs to cool the blend in an ice shower to encourage crystallization

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7 0
2 years ago
Realice las siguientes conversiones: a) 72°F a °C, b) 213.8°C a °F, c)180°C a K, d) 315K a °F, e) 1750°F a K, f) 0K a °F.
bonufazy [111]

Answer:

a) 72 °F= 22.22 °C

b)  213.8 °C=  416.84°F

c) 180 °C= 453.15 °K

d) 315 °K=  107.33 °F

e) 1750 °F= 1227.594 °K

f) 0 °K=  -459.67 °F

Explanation:

Para realizar el intercambio de unidades debes tener en cuenta las siguientes conversiones:

  • Fahrenheit a Celsius: C=\frac{F-32}{1.8}
  • Celsius a Fahrenheit: °F= °C*1.8 + 32
  • Celsius a Kelvin: °K= °C + 273.15
  • Kelvin a Fahrenheit: F= (K -273.15)*1.8 + 32
  • Fahrenheit a Kelvin:K=\frac{F-32}{1.8} + 273.15

Entonces se obtiene:

a) 72 °F= \frac{72-32}{1.8}=22.22 °C

b)  213.8 °C= 213.8*1.8 + 32= 416.84°F

c) 180 °C= 180°C + 273.15= 453.15 °K

d) 315 °K= (315 -273.15)*1.8 + 32= 107.33 °F

e) 1750 °F= \frac{1750-32}{1.8} + 273.15= 1227.594 °K

f) 0 °K= (0 -273.15)*1.8 + 32= -459.67 °F

7 0
2 years ago
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