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Daniel [21]
3 years ago
14

Shawn wants to buy a pair of gloves online. She needs to

Chemistry
1 answer:
Ksivusya [100]3 years ago
5 0
The answer would be millimeters
so answer choice d
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Ion<br> If we add an electron to a stable element we call it a(n)_____ion<br><br> anion<br> cation
masha68 [24]
The answer is a cation, I may be wrong but cation is plus and anion is subtract
3 0
3 years ago
Hook GC lsshvrrjvdjscavsbsgd​
Tema [17]

Answer:

I have no idea what that issss

Explanation:

6 0
3 years ago
Calculate the ph of a 0.17 m solution of c6h5nh3no3 (kb for c6h5nh2 = 3.8 x 10-10). record your ph value to 2 decimal places.
MatroZZZ [7]
<span>Mass of the solution = 0.17m
 Kb for C6H5NH2 = 3.8 x 10^-10
 We know Ka for C6H5NH2 = 1.78x10^-11
  We have Kw = Ka x Kb => Ka = Kw / Kb
  => (C2H5NH2)(H3O^+)/(C2H5NH3^+) => 1.78x10^-11 = K^2 / 0.17
 K^2 = 3 x 10^-12 => K = 1.73 x 10^-6.
 pH = -log(Kw(H3O^+)) = -log(1.73 x 10^-6) = 5.76</span>
6 0
3 years ago
solubility of cu(oh)2 is 2.42 x 10-3 mol/l. calculate ksp and in which direction the reaction is spontaneous if δgº
Simora [160]

Ksp of copper(II) hydroxide Cu(OH)2 is 4.9 x 10-8.

Chemical reaction (dissociation) of copper(II) hydroxide in water:

Cu(OH)2(s) → Cu²⁺(aq) + 2OH⁻(aq).

Ksp(Cu(OH)2) = [Cu²⁺]·[OH⁻]².

[Cu²⁺] = 2.42 x 10-3 mol/l; solubility od copper ions

[OH⁻] = 2[Cu²⁺] = 2 x 2.42 x 10-3 mol/l

[OH⁻] = 4.48 x 10-3 mol/l; solubility of hydroxide ions

Ksp = 2.42 x 10-3 mol/l x (4.48 x 10-3 mol/l)²

Ksp = 4.9 x 10-8

Ksp is the solubility product constant for a solid substance dissolving in an aqueous solution.

Solubility of the compound depends on the temperature of the solution and the structure of that compound.

More info about: brainly.com/question/23946616

#SPJ4

7 0
2 years ago
What is the percent of N in
Pie

Answer:

8.24

Explanation:

the answer is explained above

7 0
3 years ago
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