Point to be present exactly at midway between center and circumference of circle (let’s say radius = r) should lie at circumference of circle of radius r/2.
Favorable outcome = 2*pi*r/2
Total outcome = Point can be anywhere inside the circle of radius r = Area of circle = pi * r * r
Probability = (2*pi*r/2) / pi * r* r = 1/r.
Not completely sure about correctness . Waiting for comments to verify.
Answer:
One
Explanation:
The formulas for the two acids are CH₃CH₂COO-H and CH₃CH₂CH₂COO-H.
The key factors to consider are the polarities of the C-H and O-H bonds.
A. C-H bonds
The difference in electronegativity is ΔEN =|2.55 - 2.20| = 0.35.
This difference of so small that we usually consider the C-H bond to be nonpolar.
It is extremely unlikely that a C-H bond will dissociate onto ions.
B. O-H bonds
The difference in electronegativity is ΔEN =|3.44 - 2.20| = 1.24.
Thus, an O-H bond is highly polar covalent — the bond has about 32 % ionic character.
It is much more likely that an O-H bond will go all the way and dissociate onto ions.
RCOOH + H₂O ⇌ RCOO⁻ + H₃O⁺
The Kₐ for an O-H bond is about 10⁴⁶ times that of a C-H bond.
Only the O-H bond of a carboxylic acid will dissociate,
Answer:
I don't see any of the following. If you could possibly tell me what the following answers are in the comments I can help :)
Answer:
I think the answer is 4) 41
Explanation:
APE= atomic number, proton and the electrons are the same number
MAN= mass = atomic number - neutrons
121 - 80 = 41
i haven't done this in a while so hope this helps :)
