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bogdanovich [222]
3 years ago
8

A country's population in 1992 was 72 million. In 1998 it was 76 million. Estimate the population in 2012 using the exponential

growth formula. Round your answer to the nearest million.
P=Ae^kt
Mathematics
1 answer:
nevsk [136]3 years ago
7 0
First find the rate of growth (k)
P=Ae^kt
P 76 million
A 72 million
E constant
K ?
T time 1998-1992=6 years
Solve the formula for k
K=[log (P/A)÷log (e)]÷t
K=(log(76÷72)÷log(e))÷6
k=0.009

Now find the population in 2012
P=Ae^kt
P ?
A 72 million
E constant
K 0.009
T time 2,012−1,992=20 years

P=72×e^(0.009×20)
p=86 million. In 2012
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Simplify the following expression: (5x2 + 3x + 4) − (2x2 + 7x − 1). If the final answer is written in the form Ax2 + Bx + C, wha
Andrews [41]

Answer:

 

3x + 2x2 + 4 = 5

3x + 2x2 + 4 – 5 = 5 – 5

First be sure that the right side of the equation is 0. In this case, all you need to do is subtract 5 from both sides.

 

3x + 2x2 – 1 = 0

2x2 + 3x – 1 = 0

Simplify, and write the terms with the exponent on the variable in descending order.

 

2x2

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ax2

 

bx

 

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a = 2, b = 3, c = −1

 

Now that the equation is in standard form, you can read the values of a, b, and c from the coefficients and constant. Note that since the constant 1 is subtracted, c must be negative.

Answer

2x2 + 3x – 1 = 0; a = 2, b = 3, c = −1

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The 9th and the 12th term of an arithmetic progression are 50 and 65 respectively. find the common difference
Rzqust [24]

The first term of the arithmetic progression exists at 10 and the common difference is 2.

<h3>How to estimate the common difference of an arithmetic progression?</h3>

let the nth term be named x, and the value of the term y, then there exists a function y = ax + b this formula exists also utilized for straight lines.

We just require a and b. we already got two data points. we can just plug the known x/y pairs into the formula

The 9th and the 12th term of an arithmetic progression exist at 50 and 65 respectively.

9th term = 50

a + 8d = 50 ...............(1)

12th term = 65

a + 11d = 65 ...............(2)

subtract them, (2) - (1), we get

3d = 15

d = 5

If a + 8d = 50 then substitute the value of d = 5, we get

a + 8 * 5 = 50

a + 40 = 50

a = 50 - 40

a = 10.

Therefore, the first term is 10 and the common difference is 2.

To learn more about common differences refer to:

brainly.com/question/1486233

#SPJ4

4 0
2 years ago
Given that F( x ) = x 2 + 2, evaluate F(1) + F(5).
stealth61 [152]

Hi there! :)

Answer:

\huge\boxed{f(1) + f(5) = 30}

Given:

f(x) = x^{2} + 2

Evaluate f(1) + f(5)

Solve for each:

f(1) = (1)^{2} +  2 = 3

f(5) = (5)^{2} + 2 = 27

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3 0
3 years ago
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Find the solutions of the quadratic equation -9c² +2 +3 = 0.
Tresset [83]

Given that,

An equation : -9c² +2c +3 = 0

To find,

Find the value of x.

Solution,

We have, -9c² +2c +3 = 0

We can solve it using the formula as follows :

x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

Here, a = -9, b = 2 and c =3

Put the values,

c=\dfrac{-2\pm \sqrt{(2)^2-4(-9)(3)}}{2(-9)}\\\\c=\dfrac{-2+\sqrt{(2)^{2}-4(-9)(3)}}{2(-9)}, \dfrac{-2-\sqrt{(2)^{2}-4(-9)(3)}}{2(-9)}\\\\c=-0.47, 0.69

So, the solution are -0.47 and 0.69.

8 0
3 years ago
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liberstina [14]

Answer:

the answer is 18

Step-by-step explanation:

9root3/sin60

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