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3 years ago

According to the Fundamental Theorem of Algebra, how many roots exist for the polynomial function?

Mathematics

2 answers:

RideAnS [48]3 years ago

4 0

Three! -7/9, -1/4, and -4/3

garri49 [273]3 years ago

3 0

Answer with Step-by-step explanation:

The fundamental theorem of algebra states that every non-constant single-variable polynomial with complex coefficients has at least one complex root. This includes polynomials with real coefficients, since every real number can be considered a complex number with its imaginary part equal to zero.

Hence, the given polynomial equation has atleast 1 real root and atmost 3 real roots

(9x + 7)(4x + 1)(3x + 4) = 0

On solving this, we get

9x+7=0 or 4x+1=0 or 3x+4=0

i.e. x= -7/9 or x= -1/4 or x= -4/3

As we can see all the roots are real

Hence, number of real roots are:

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Write a paragraph comparing the two classes' semester grades. Be sure to compare the extremes, the quartiles, the medians, and t

NISA [10]

Answer:

Class second have higher score and have greater spread.

Step-by-step explanation:

For first box plot

$\text{Minimum value }= 53$

$Q_1=62$

$Median=80$

$Q_3=86$

$\text{Maximum value }= 89$

$Range=Maximum-Minimum=89-53=36$

$IQR=Q_3-Q-1=86-62=24$

For second box plot

$\text{Minimum value }= 56$

$Q_1=62$

$Median=74$

$Q_3=89$

$\text{Maximum value }= 96$

$Range=Maximum-Minimum=96-56=40$

$IQR=Q_3-Q-1=89-62=27$

First class has greater minimum value, it means first class has lower grades.

First quartile of both classes are same, it means equal number students in both classes have less than 62 marks.

First class has greater median.

second class has greater third quartile.

Second class has greater Maximum value. It means second class have higher score than first class.

Second class has greater range. It means the data of second class has greater spread.

Second class has greater inter quartile range. It means the data of second class has greater spread.

Therefore, the class second have higher score and have greater spread.

5 0

3 years ago

Find the area of the shaded region .

Greeley [361]

Calculate area of the white region inside circle.

Area of the two white triangles in top left and bottom right:

$2 \cdot \frac{1}{2}(6)(6) = 36 ft^2$

Area of the two white quarter circles in the bottom left and top right:

$2 \cdot \frac{1}{4}\pi (6)^2 = 18\pi ft^2$

Total area of unshaded white region inside circle:

$(36 + 18\pi)ft^2$

Area of entire circle including the white and shaded regions

$\pi(6)^2 = 36\pi ft^2$

Area of shaded region is area of entire circle - area of unshaded white region

$36\pi - (36 + 18\pi) = (18\pi - 36) ft^2$

7 0

2 years ago

BRAINLIEST

Anna71 [15]

Answer:

h(x)

f(x) g(x) h(x)

Step-by-step explanation:

Edge 2020

~theLocoCoco

6 0

3 years ago

Round to the nearest tenth: 6.932635<br> 6.9<br> 6<br> 6.8<br> 7

Lera25 [3.4K]

6.932635
^ This is the tenths place.

Since the number after it is less than 5, we round down.

So we round to:

6.9

7 0

3 years ago

Read 2 more answers

Find the sine of ∠E.

chubhunter [2.5K]

Answer:

solution

by using pythagorus theorem

h^2 =p^2 +b^2

10^2 = p^2 +under root 82 square

<h2>therefore p is equal to </h2>

$3 \sqrt{2} \\$

sine E =p/h

$3 \sqrt{2} \div 10$

5 0

3 years ago

Read 2 more answers