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kondaur [170]
3 years ago
14

According to the Fundamental Theorem of Algebra, how many roots exist for the polynomial function?

Mathematics
2 answers:
RideAnS [48]3 years ago
4 0
Three! -7/9, -1/4, and -4/3
garri49 [273]3 years ago
3 0

Answer with Step-by-step explanation:

The fundamental theorem of algebra states that every non-constant single-variable polynomial with complex coefficients has at least one complex root. This includes polynomials with real coefficients, since every real number can be considered a complex number with its imaginary part equal to zero.

Hence, the given polynomial equation has atleast 1 real root and atmost 3 real roots

(9x + 7)(4x + 1)(3x + 4) = 0

On solving this, we get

9x+7=0  or  4x+1=0  or 3x+4=0

i.e.  x= -7/9  or  x= -1/4  or  x= -4/3

As we can see all the roots are real

Hence, number of real roots are:

3

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Step-by-step explanation:

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Answer:

WX = 9

Step-by-step explanation:

WY is the entire line - this tells you that the length of the entire line is 11.

XY is a section of the line, and WX is the section you need to find the length for. Since it is given that XY is of length 2, we can find the length of WX by subtracting the length of XY from WY.

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Find the greatest common factor of the following monomials 26n5 12n2
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