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Vitek1552 [10]
3 years ago
7

The melting point of a substance occurs at the same temperature as its _____ point. A. boiling B. freezing C. condensing

Chemistry
2 answers:
shusha [124]3 years ago
8 0
A) Boiling point. :)
guajiro [1.7K]3 years ago
4 0

just took this quiz and the answer is A. boiling point


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The specific heat of wood is 2.03 J/g.°C. How much
Brilliant_brown [7]

Answer:

11419 J/g/ 11.419 KJ/g

Explanation:

H=MCQ

H=225×2.03×(-15-10)

H=225×2.03(25) Note; negative sign is of no use

H=11419J/g

3 0
3 years ago
Calculate the mass of 2.50 mol of methanol.
solmaris [256]

Answer:

60g

Explanation:

Moles = mass / mollar mass

Mass = Moles x mollar mass

Mass = 2.50 x 24

Mass = 60g

7 0
3 years ago
Read 2 more answers
Aluminum reacts with sulfur gas to produce aluminum sulfide. a) What is the limiting reactant? What is the excess reagent? b) Ho
Sophie [7]

Answer:

a) Limiting: sulfur. Excess: aluminium.

b) 1.56g Al₂S₃.

c) 0.72g Al

Explanation:

Hello,

In this case, the initial mass of both aluminium and sulfur are missing, therefore, one could assume they are 1.00 g for each one. Thus, by considering the undergoing chemical reaction turns out:

2Al(s)+3S_2(g)\rightarrow 2Al_2S_3(s)\\

a) Thus, considering the assumed mass (which could be changed based on the one you are given), the limiting reagent is identified as shown below:

n_S^{available}=1.00gS_2*\frac{1molS_2}{64gS_2} =0.0156molS_2\\n_S^{consumed\ by \ Al}=1.00gAl*\frac{1molAl}{27gAl}*\frac{3molS_2}{2molAl}=0.0556molS_2

Thereby, since there 1.00g of aluminium will consume 0.0554 mol of sulfur but there are just 0.0156 mol available, the limiting reagent is sulfur and the excess reagent is aluminium.

b) By stoichiometry, the produced grams of aluminium sulfide are:

m_{Al_2S_3}=0.0156molS_2*\frac{2molAl_2S_3}{3molS_2} *\frac{150gAl_2S_3}{1molAl_2S_3} =1.56gAl_2S_3

c) The leftover is computed as follows:

m_{Al}^{excess}=(0.0556-0.0156)molS_2*\frac{2molAl}{3molS_2}*\frac{27gAl}{1molAl} =0.72 gAl\\

NOTE: Remember I assumed the quantities, they could change based on those you are given, so the results might be different, but the procedure is quite the same.

Best regards.

7 0
3 years ago
Draw a bond-line structure for CH3CH2O(CH2)2CH(CH3)2.<br><br> Include Lone Pairs in your answer.
mash [69]

Answer:

See explanation and image attached

Explanation:

A bond line structure refers to any structure of a covalent molecule wherein the covalent bonds present in the molecule are represented with a single line for each level of bond order.

The bond-line structure of CH3CH2O(CH2)2CH(CH3)2 has been shown in the image attached. We know that oxygen has a lone pair of electrons and this has been clearly shown also in the image attached.

7 0
3 years ago
A 100-w light bulb is about 16% efficient. how many joules of heat energy are siddipated by the bulb each second
pickupchik [31]

Answer:

84 Joules are wasted per second.

Explanation:

An efficiency of 16% means 84% is wasted as heat energy.  

Therefore;

For a 100W bulb;

Heat wasted = 84/100 × 100 W

                      = 84 W

Therefore;

84 W or 84 joules are wasted as heat per second

3 0
3 years ago
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