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kherson [118]
3 years ago
8

Acids & bases/concentration A mixture is made by mixing 425 mL of 0.94 M H2SO4 with 750. mL of 0.83 M NaOH. (a) What is the

limiting reactant? (b) How much excess reactant will be left over? (c) Is this mixture acidic or basic? Why? (d) What is the concentration of the [H+] or [OH-] ions that remain in this solution? (e) Calculate the pH of this solution.
Chemistry
1 answer:
Ksenya-84 [330]3 years ago
4 0

Answer:

I'm really sorry but I didn't understand your question

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HEEEEELP ASAPP IM AWARDING 30 points!!!!
alexira [117]

Answer:

\rm S^{2-}.

Explanation:

Based on the electron configuration of this ion, count the number of electrons in this ion in total:

2 + (2 + 6) + (2 + 6) = 18.

Each electron has a charge of (-1).

Atoms are neutral and have 0 charge. However, when an atom gains one extra electron, it becomes an ion with a charge of (-1). Likewise, when that ion gains another electron, the charge on this ion would become (-2).

The ion in this question has a charge of (-2). In other words, this ion is formed after its corresponding atom gains two extra electrons. This ion has 18 electrons in total. Therefore, the atom would have initially contained 18 - 2 = 16 electrons. The atomic number of this atom would be 16.

Refer to a modern copy of the periodic table. The element with an atomic number of 16 is sulphur with atomic symbol \rm S. To denote the ion, place the charge written backwards ("2-" for a charge of (-2)) as the superscript of the atomic symbol:

\rm S^{2-}.

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