The energy source used in nuclear power plants today is

A 1.0 L sample of an aqueous solution contains 0.10 mol of NaCl and 0.10 mol of CaCl2. What is the minimum number of moles of Ag

Annette [7]

Answer:

The answer to your question is: 0.3 moles of AgNO₃

Explanation:

1.0 L sample

0.1 mol of NaCl

0.1 mol of CaCl₂

AgNO₃ = ? moles

Reactions

NaCl + AgNO₃ ⇒ AgCl + NaNO₃

Then 1 NaCl mol --------------- 1 AgNO₃

0.1 mol -------------- x

x = 0.1 moles of AgNO₃ needed

CaCl₂ + 2 AgNO₃ ⇒ 2 AgCl + Ca(NO₃)₂

Then 1 mol of CaCl₂ ------------- 2 moles of AgNO₃

0.1 mol ------------- x

x = 0.2 moles of AgNO₃

Total moles of AgNO₃ = 0.1 + 0.2 = 0.3

5 0

3 years ago

How many grams of C6H6O3 will react with 97.0grams of O2?<br><br> C6H6O3+3O2 ===> 6CO+3H2O

likoan [24]

Answer:

127.3 g

Explanation:

Data Given

mass of O₂= 97 g

mass of C₆H₆O₃ = ?

Reaction Given:

C₆H₆O₃ + 3O₂ --------> 6CO + 3H₂O

Solution:

First find the mass of C₆H₆O₃ from the reaction that it combine with how many grams of oxygen (O₂).

Look at the balanced reaction

C₆H₆O₃ + 3O₂ --------> 6CO + 3H₂O

1 mol 3 mol

So 1 mole of C₆H₆O₃ combine with 3 moles of O₂

Now

convert the moles into mass for which we have to know molar mass of C₆H₆O₃ and O₂

Molar mass of C₆H₆O₃

Molar mass of C₆H₆O₃ = 6(12) + 6(1) +3(16) = 72 + 6 + 48

Molar mass of C₆H₆O₃ = 126 g/mol

mass of C₆H₆O₃

mass in grams = no. of moles x molar mass

mass of C₆H₆O₃ = 1 mol x 126 g/mol

mass of C₆H₆O₃ = 126 g

Molar mass of O₂ = 2(16)

Molar mass of O₂= 32 g/mol

mass of O₂

mass in grams = no. of moles x molar mass

mass of O₂ = 3 mol x 32 g/mol

mass of O₂ = 96 g

So,

96 g of O₂ combine with 126 g of C₆H₆O₃ then how many grams of C₆H₆O₃ will combine with 97.0grams of O2

Apply unity Formula

96 g of O₂ ≅ 126 g of C₆H₆O₃

97 g of O₂ ≅ X g of C₆H₆O₃

By cross multiplication

X g of O₂ = 126 g x 97 g / 96 g

X g of O₂ = 127.3 g

127.3 g of C₆H₆O₃ will combine with 97 g of O₂

So

mass of C₆H₆O = 127.3 g

7 0

3 years ago

Commercial products commonly report concentration in terms of "percentage." Using this

Stella [2.4K]

The answer to the question is 0.8055 as the answer should not include units in it.

Molarity (M) = n/v

n = moles of solute

v = liters of solution

According to question

1% solution → 1 gram of solute for 100 milliliters of solution

2% solution → 2 grams of solute for 100 milliliters of solution

6% NaClO solution → 6 grams of NaClO (solute) for 100 milliliters of solution

Molar mass of NaClO = (22.98 + 35.5 + 16)g/mol = 74.48 g/mol

Atomic mass of Na = 22.98 g/mol

Atomic mass of Cl = 35.5 g/mol

Atomic mass of O = 16 g/mol

1 mol NaClO = 74.48 grams NaClO

74.48 grams NaClO = 1 mol NaClO

6 grams NaClO = (1×6) / 74.48 mole = 0.08055 mole

As unit molarity is mole / liter

So 100 milliliters = 0.1 liters

1 liter = 1000 milliliters

100 milliliters = 100/1000 liters = 0.1 liters

Molarity of NaClO = moles of solute (NaClO) / liters of solution or volume of solution

Molarity of NaClO = 0.08055 / 0.1 mole/L = 0.8055 mole/L

As in question it is mentioned that 'Do not type units into your answer'

So, Molarity of NaClO in clorox bleach = 0.8055

Thus we find out the value of molarity of NaClO in Clorox bleach which came out to be 0.8055 as we dont have to give the answer with units.

Learn more about Molarity here:

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8 0

2 years ago

According to the iupac convention, alkyl substituents on a hydrocarbon chain should be listed in which order?

Scilla [17]

According to the IUPAC convention alkyl substituents on a hydrocarbon chain should be listed in alphabetical without considering prefixes order.

<h3>What is IUPAC convention?</h3>

IUPAC convention of organic chemistry is a method of naming organic chemical compounds as recommended by the International Union of Pure and Applied Chemistry (IUPAC).

The name of the compound is written out with the substituents in alphabetical order followed by the base name (derived from the number of carbons in the parent chain).

Types of IUPAC Nomenclature of a few important aliphatic compounds:

Alkane
Alkene
Alkyne

Example :

Ethane, which has 2 carbon atoms and 6 hydrogen atoms, with the molecular formula of = C₂H₆

Formation of alkyl group:

Methane (CH₄) Remove 1 hydrogen (H) convert to methyl (H₃-C-)

Example: Propyl (-CH₃ - CH₂ - CH₂ - )

According to the IUPAC convention alkyl substituents on a hydrocarbon chain should be listed in alphabetical without considering prefixes order.

Learn more about IUPAC convention, Here:

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8 0

2 years ago

Air blows at the base of circulation cells from ________ pressure to ________ pressure

Nataly [62]

air blows at the base of circulation cells from high pressure to low pressure

3 0

3 years ago