Answer:
<u>Balanced equation:</u>
![Pb(NO_{3})_{2}(aq)+K_{2}CO_{3}(aq)\rightarrow PbCO_{3}(s)+2KNO_{3}(aq)](https://tex.z-dn.net/?f=Pb%28NO_%7B3%7D%29_%7B2%7D%28aq%29%2BK_%7B2%7DCO_%7B3%7D%28aq%29%5Crightarrow%20PbCO_%7B3%7D%28s%29%2B2KNO_%7B3%7D%28aq%29)
Explanation:
The chemical reaction between Lead(II) Nitrate and potassium carbonate is as follows.
![Lead(II)Nitrate+Potassium\,carbonate \rightarrow Lead(III)\,\,carbonate+Potassium\,nitrate](https://tex.z-dn.net/?f=Lead%28II%29Nitrate%2BPotassium%5C%2Ccarbonate%20%5Crightarrow%20Lead%28III%29%5C%2C%5C%2Ccarbonate%2BPotassium%5C%2Cnitrate)
![Pb(NO_{3})_{2}(aq)+K_{2}CO_{3}(aq)\rightarrow PbCO_{3}(s)+2KNO_{3}(aq)](https://tex.z-dn.net/?f=Pb%28NO_%7B3%7D%29_%7B2%7D%28aq%29%2BK_%7B2%7DCO_%7B3%7D%28aq%29%5Crightarrow%20PbCO_%7B3%7D%28s%29%2B2KNO_%7B3%7D%28aq%29)
<u>Ionic equation:</u>
![Pb^{2+}(aq)+2NO_{3}^{-}(aq)+2K^{+}(aq)+CO_{3}^{2-}(aq)\Leftrightarrow PbCO_{3}(s)+K^{+}(aq)+2NO_{3}^{-}](https://tex.z-dn.net/?f=Pb%5E%7B2%2B%7D%28aq%29%2B2NO_%7B3%7D%5E%7B-%7D%28aq%29%2B2K%5E%7B%2B%7D%28aq%29%2BCO_%7B3%7D%5E%7B2-%7D%28aq%29%5CLeftrightarrow%20PbCO_%7B3%7D%28s%29%2BK%5E%7B%2B%7D%28aq%29%2B2NO_%7B3%7D%5E%7B-%7D)
Cancel the same ions on the both sides of the reaction.
The net ionic equation is as follows.
![Pb^{2+}(aq)+CO_{3}^{2-}(aq)\Leftrightarrow PbCO_{3}(s)](https://tex.z-dn.net/?f=Pb%5E%7B2%2B%7D%28aq%29%2BCO_%7B3%7D%5E%7B2-%7D%28aq%29%5CLeftrightarrow%20PbCO_%7B3%7D%28s%29)
Answer:
If the question is which can make a buffer, then NH3, NH4Cl should be correct. Because Ammonium (NH4) is conjugate acid of NH3 so they can form an equilibrium which is basically a buffer whose purpose is to resist pH change.
Explanation:
Answer:
you dont do anything because then you are supporting it
if u add something
Explanation:
Answer:
5.79 × 10^23 Oxygen atoms
Explanation:
Number of Oxygen atom in the compound = 4×3 = 12
Molar mass of Al2(SO4)3 = 342 g/mol.
No of mole = mass/molar mass = 2.74/342 = 8.01×10^-03 mole
2.74g of Al2(SO4)3 × 1 mole of Al2 (SO4)3 / 342g of Al2 (SO4)3 * 12 mole of Oxygen/ 1mole of Al(SO4)3 * 6.02×10^23 Oxygen atom/ 1 mole of Oxygen
= 5.79×10^23 Oxygen atoms