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Ilia_Sergeevich [38]
3 years ago
14

What is the measure of segment JK? Do not round

Mathematics
1 answer:
V125BC [204]3 years ago
6 0
The correct answer is 8.4
becaues the midsegment MP is 4.2 


4.2 x 2 = 8.4
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Find 0.45 of 80 A.36 B.3.6 C.0.36 D.0.036
andrew-mc [135]

A

the word 'of' means to multiply

0.45 × 80 = 36


8 0
3 years ago
1. 8 - n = -4
iogann1982 [59]

Answer:

1.-n=-12; n=12

2.18=-2x; x=-9

3.-n=-12; n=12

4.b=3


4 0
4 years ago
Consider a sequence defined by the recursive rule f(1) = 15; f(n)=f(n - 1) - 6 for n 2. Choose True or
Shkiper50 [21]

Answer:

The second term of the sequence is 8  False ⇒ B

The third term of the sequence is 3  True ⇒ A

The fourth term of the sequence is -3  True ⇒ A

Step-by-step explanation:

The form of the recursive rule is:

f(1) = first term; f(n) = f(n - 1) + d, where

  • f(1) is the first term
  • f(n) is the nth term
  • f(n - 1) is the term before the nth term
  • d is the common difference

∵ f(1) = 15, f(n) = f(n - 1) - 6 for n ≥ 2

∴ The first term = 15

∴ d = -6

let us find the 2nd, 3rd, and 4th terms

∵ n = 2

∴ f(2) = f(1) - 6

∵ f(1) = 15

∴ f(2) = 15 - 6 = 9

∴ The second term is 9

∴ The second term of the sequence is 8  False

∵ n = 3

∴ f(3) = f(2) - 6

∵ f(2) = 9

∴ f(3) = 9 - 6 = 3

∴ The third term is 3

∴ The third term of the sequence is 3 True

∵ n = 4

∴ f(4) = f(3) - 6

∵ f(3) = 3

∴ f(4) = 3 - 6 = -3

∴ The fourth term is -3

∴ The fourth term of the sequence is -3 True

5 0
4 years ago
Find the slope of the line that contains the points (-5, 3) and (-1,-5).<br>​
Nutka1998 [239]

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>⤴</em>

<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>.</em>

8 0
3 years ago
2x + 3 + 4x + 8 = 3x - 10
vodomira [7]

\text {Hello! Let's solve this Equation!}

\text {Your First Step is to Simplify the Equation:}

\text {(2x+4x)+(8+3)}

\text {6x+11=3x-10}

\text {The Next Step is to Subtract 3x:}

\text {6x+11-3x=3x-10-3x}\\\text {3x+11=-10}

\text {Next Step is to Subtract 11:}

\text {Q: Why Subtract 11?}

\text {A: So they cancel out. We cross them out once we subtract.}

\text {3x+11-11=-10-11}\\\text {3x=-21}

\text {The Final Step is to Divide 3:}

\text {3x/3=-21/3}

\text {Your Answer will be}

\fbox {x=-7}

\text {Best of Luck!}

\text {-LimitedX}

8 0
3 years ago
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