Answer:
The angle will be 0 . The angle between the incident ray and the mirror is called angle of incidence while the angle between reflected ray and the normal is called angle of reflection. Here, the a ray of light is incident normally on a plane mirror.
Explanation:
Answer:
The thermal conductivity of the wall = 40W/m.C
h = 10 W/m^2.C
Explanation:
The heat conduction equation is given by:
d^2T/ dx^2 + egen/ K = 0
The thermal conductivity of the wall can be calculated using:
K = egen/ 2a = 800/2×10
K = 800/20 = 40W/m.C
Applying energy balance at the wall surface
"qL = "qconv
-K = (dT/dx)L = h (TL - Tinfinity)
The convention heat transfer coefficient will be:
h = -k × (-2aL)/ (TL - Tinfinty)
h = ( 2× 40 × 10 × 0.05) / (30-26)
h = 40/4 = 10W/m^2.C
From the given temperature distribution
t(x) = 10 (L^2-X^2) + 30 = 30°
T(L) = ( L^2- L^2) + 30 = 30°
dT/ dx = -2aL
d^2T/ dx^2 = - 2a
Distance = velocity
time distance = 50 km/h x .5 hour distance so your answer would be 25km
Answer:
D. 2.7 N
Explanation:
Applying
F = kq'q/r²................ Equation 1
Where F = force, k = coulomb's constant, q' = first charge, q = second charge, r = distance between the charge
From the question,
Given: q' = +3.0×10⁻⁷ C, q = +4.0×10⁻⁷C, r = 2.0×10⁻² m
Constant: k = 8.98×10⁹ Nm²/C²
Substitute these values into equation 1
F = ( +3.0×10⁻⁷)(+4.0×10⁻⁷)(8.98×10⁹)/(2.0×10⁻²)²
F = 26.94×10⁻¹ N
F = 2.694 N
F ≈ 2.7 N
Answer:
i think answer should be C