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3 years ago

If you have the equation

1 answer:

6 0

Assuming the conditions of the reaction are maintained and appropriate for the reaction to still occur, the reaction rate can be affected by increasing the concentration of the reagents used in a reaction. It will speed it up.

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Which of the following elements is a representative element?

Lubov Fominskaja [6]

B. aluminum is the representative element. :)

5 0

3 years ago

In the following reaction the iodide ion (I-) in HI is oxidized by the permanganate ion (MnO4-). A 5.0 mL solution of 0.20M HI r

katrin [286]

Answer:

The molarity of the KMnO4 solution is 0.05M (option 1)

Explanation:

10 HI + 2 KMnO4 + 3 H2SO4 → 5 I2 + 2 MnSO4 + 8 H2O

This is the base.

10 moles of HI need 2 moles of KMnO4, to make 5 moles of I2 (gas)

Our solution of HI is 0,20 M which means 0,2 moles in 1 L of solution but we used 5 mL, so how many moles did we use?

Molarity . volume = Moles

0.2 moles/L . 0.005L = 0.001 moles

Notice, we had to convert 5 mL into 0.005 L

So, let's go back to begining: 10 moles of HI need 2 moles of KMnO4.

How many moles of salt, do we need for 0.001 moles of HI.

The rule of three is:

10 moles of HI ___ need ___ 2 moles of KMnO4

0.001 moles of HI __ need ___ (0.001 . 2 ) / 10 = 0.0002 moles

This is our quantity of moles, that we need from KMnO4 but this moles are in 4 mL.

Molarity = moles / L but we can also take account molarity as mM / mL (Molarity/1000)

0.0002 moles . 1000 = 0.2 mM

0.2 mM / 4mL = 0.05 M

6 0

3 years ago

A student wants to prepare 250.0 mL of 0.10 M NaCl solution. Which procedure is most appropriate? (formula Molar Mass of NaCl =

Anvisha [2.4K]

The correct answer is option B, that is, add 1.46 grams of NaCl to 250 milliliters of H₂O.

First there is a need to find the moles of NaCl in 250 ml of 0.10 M NaCl,

Moles of NaCl = molarity × volume = 0.10 M × (250/1000L) = 0.025 mol

The corresponding mass of NaCl is,

Mass of NaCl = moles × molar mass = 0.025 mol × 58.5 g/mol = 1.46 g

Thus, there is a need to dissolve 1.46 grams of NaCl solid into 50 ml of H₂O and dilute to 250 ml.

3 0

3 years ago

PLEASE HELP

devlian [24]

Metals have a low electron affinity- a less likely chance to gain electrons because they want to give up their valence electrons rather than gain electrons, which require more energy than necessary.

6 0

3 years ago

Drag each label to the correct location on the table.

AleksAgata [21]

Explanation:

1) Boyle's Law: This law states that pressure is inversely related to the volume occupied by the gas at constant temperature and number of moles.

$P\propto \frac{1}{V}$ (At constant temperature and number of moles)

When the size of the chamber is increased the volume occupied the gas will increase with which pressure exerted by the gas will decrease down.
When we press the inflated balloon the pressure on the gas is increased with which volume of the occupied by the gas inside the balloon decreased.

2) Charles' Law: This law states that volume occupied by the gas is directly related to the temperature of the gas at constant pressure and number of moles.

$V\propto T$ (At constant pressure and number of moles)

The size of the balloon deceases because the in winters the temperature decreases with which volume of the gas present in the balloon also decreases.
When the flexible closed container is heated the temperature of the gas inside the container increases with which the volume occupied by the gas in the container will increase resulting in expanding of container.

3) Avogadro's Law: This law states that volume occupied by the gas is directly related to the number of moles of the gas at constant pressure and temperature.

$V\propto n$ (At constant temperature and pressure)

When we blow air into the balloon the umber of air particles increases with which the volume of the gas inside the balloon also increases resulting in increase in size of the balloon.

3 0

3 years ago