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Luden [163]
3 years ago
5

What is the value of X in the equation shown? 8*4=(x*7)-(x*3)

Mathematics
1 answer:
Oksana_A [137]3 years ago
7 0
8·4=(x·7)-(x·3)
32=7x-3x
32=4x
x=8
This is your answer.
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(a) A square has a perimeter of 12 cm. What is the length of each side?
myrzilka [38]

Answer:

P = 4 c

12 = 4 c

3 = c

Step-by-step explanation:

Hope this helps.

7 0
2 years ago
What property is illustrated in this equation?
Lerok [7]
In the equation given, the Distributive Property is being demonstrated.
8 0
3 years ago
Suppose a batch of metal shafts produced in a manufacturing company have a population standard deviation of 1.3 and a mean diame
lbvjy [14]

Answer:

54.86% probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 208, \sigma = 1.3, n = 60, s = \frac{1.3}{\sqrt{60}} = 0.1678

What is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

Lesser than 208 - 0.1 = 207.9 or greater than 208 + 0.1 = 208.1. Since the normal distribution is symmetric, these probabilities are equal, so we find one of them and multiply by 2.

Lesser than 207.9.

pvalue of Z when X = 207.9. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{207.9 - 208}{0.1678}

Z = -0.6

Z = -0.6 has a pvalue of 0.2743

2*0.2743 = 0.5486

54.86% probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

6 0
3 years ago
Find the x,length and width.
Paraphin [41]

Answer:

3 qnd 8 is the answer

Step-by-step explanation:

7 0
3 years ago
Whats the answers can anyone answer this question please​
topjm [15]

Answer:

1. B

2. A

Step-by-step explanation:

1.

10^{-2} means that you move the decimal back two times

B is the only option that represents that correctly.

2.

5 * 10^{4} = 50000

2.5 * 10^{2} = 250

50000/250 = 200

Out of the options, A is the only option in which the equation also equals 200.

4 0
2 years ago
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