All categories

3 years ago

How many Moles of NAOH are present in 2.50L of 0.300 M NaOH?

Chemistry

1 answer:

maw [93]3 years ago

8 0

<h3>Answer:</h3>

0.75 moles NaOH

<h3>Explanation:</h3>

We are given;

Volume of NaOH solution = 2.5 Liters

Molarity of NaOH = 0.300 M

We are required to calculate the moles of NaOH

We need to establish the relationship between moles, molarity and volume of a solution.

That would be;

Concentration/molarity = Moles ÷ Volume

Therefore;

Moles = Concentration × Volume

Thus;

Moles of NaOH = 0.300 moles × 2.50 L

= 0.75 moles

Therefore, the number of moles of NaOH is 0.75 moles

You might be interested in

Whuch expression is equal to the number of grams in 2.43 kg

schepotkina [342]

2.43*1000.

There are 1000 grams in a kilogram

7 0

3 years ago

At 700 K, the reaction 2SO2(g) + O2(g) <====> 2SO3(g) has the equilibrium constant Kc = 4.3 x 106. At a certain instant, f

nadya68 [22]

Answer:

The system is not in equilibrium and will evolve left to right to reach equilibrium.

Explanation:

The reaction quotient Qc is defined for a generic reaction:

aA + bB → cC + dD

$Q=\frac{[C]^{c} *[D]^{d} }{[A]^{a}*[B]^{b} }$

where the concentrations are not those of equilibrium, but other given concentrations

Chemical Equilibrium is the state in which the direct and indirect reaction have the same speed and is represented by a constant Kc, which for a generic reaction as shown above, is defined:

$Kc=\frac{[C]^{c} *[D]^{d} }{[A]^{a}*[B]^{b} }$

where the concentrations are those of equilibrium.

This constant is equal to the multiplication of the concentrations of the products raised to their stoichiometric coefficients divided by the multiplication of the concentrations of the reactants also raised to their stoichiometric coefficients.

Comparing Qc with Kc allows to find out the status and evolution of the system:

If the reaction quotient is equal to the equilibrium constant, Qc = Kc, the system has reached chemical equilibrium.

If the reaction quotient is greater than the equilibrium constant, Qc> Kc, the system is not in equilibrium. In this case the direct reaction predominates and there will be more product present than what is obtained at equilibrium. Therefore, this product is used to promote the reverse reaction and reach equilibrium. The system will then evolve to the left to increase the reagent concentration.

If the reaction quotient is less than the equilibrium constant, Qc <Kc, the system is not in equilibrium. The concentration of the reagents is higher than it would be at equilibrium, so the direct reaction predominates. Thus, the system will evolve to the right to increase the concentration of products.

In this case:

$Q=\frac{[So_{3}] ^{2} }{[SO_{2} ]^{2}* [O_{2}] }$

$Q=\frac{10^{2} }{0.10^{2} *0.10}$

Q=100,000

100,000 < 4,300,000 (4.3*10⁶)

Q < Kc

<u><em> The system is not in equilibrium and will evolve left to right to reach equilibrium.</em></u>

3 0

3 years ago

In a solution of salt and water which component is the salute A salt B water C speaker D oxygen

Wewaii [24]

Hi thereeeeeeeeeee! salt is ur answer !

8 0

3 years ago

Read 2 more answers

Order the bowls from coolest to warmest

vampirchik [111]

Answer:

bowl 5, bowl 3, bowl 4, bowl 1, bowl 2

Explanation:

3 0

3 years ago

Which polyatomic ion is found in the compound represented by the formula NaHCO3?

stiv31 [10]

Answer: The correct option is 2.

Explanation: Polyatomic ions are defined as the ions in which two or more elements are covalently bonded to act as a single unit. They always carry some charge.

Examples of polyatomic ions are: $OH^-$ known as hydroxide ion, $SO_4^{2-}$ known as sulfate ion

We are given a compound $NaHCO_3$ having 2 ions which are $Na^+$ and $HCO_3^-$ . these ions are named as sodium ions and hydrogen carbonate ions.

Therefore, the correct option is 2.

8 0

3 years ago

Read 2 more answers