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Mila [183]
1 year ago
15

calculate the quantity of 0.001 m aq naoh needed to neutralize the hcl produced by complete solvolysis

Chemistry
1 answer:
abruzzese [7]1 year ago
5 0

The quantity of 0.001 m aq naoh needed to neutralize the hcl produced by complete solvolysis is 200 ml.

Solvolysis is a type of nucleophilic substitution or elimination wherein the nucleophile is a solvent molecule. function of SN1 reactions, solvolysis of a chiral reactant provides the racemate.

Calculation :-

using the titration equation,

M₁V₁ = M₂V₂

substituting values

V₁ = M₂ V₂/M₁

  = 0.2 × 10 ml /0.01

= 2/0.01 ml

= 200 ml.

A reaction in which the solvent is a reactant, and turns into part of the response product. Hydrolysis of tert-butyl chloride; solvent = water. Fischer esterification reaction; solvent = methanol. related phrases: Alcoholysis, aminolysis.

Learn more about solvolysis here:-brainly.com/question/29555642

#SPJ4

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<u>Disclaimer:- your question is incomplete, please see below for the complete question.</u>

Calculate the quantity of 0.01M aq NaOH needed to neutralize the HCl produced by complete solvolysis of the t-BuCl in 10ml of 0.2M t-BuCl in acetone.

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When comparing propionic acid (CH3CH2COOH) and sodium propionate (CH3CH2COONa), the one that is more soluble in water is When co
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Answer:

When comparing propionic acid (CH₃CH₂COOH) and sodium propionate (CH₃CH₂COONa), the one that is more soluble in water sodium propionate.

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When comparing hydrochloric acid (HCl) and ethyl chloride (CH3CH2Cl), the one that is more soluble in water is hydrochloric acid

Explanation:

When comparing propionic acid (CH₃CH₂COOH) and sodium propionate (CH₃CH₂COONa), the one that is more soluble in water sodium propionate. Because always a salt is more soluble in water than its acid (Solubility of propionic acid is 0,37g/mL and of sodium propionate is 1g/mL).

When comparing cyclohexane (C6H12) and glucose (C6H12O6), the one that is more soluble in water is glucose because cyclohexane is made from petroleum and its polarity is very low (cyclohexane is insoluble in water and solubility of glucose is 0,91g/mL).

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I hope it helps!

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3 years ago
A cube is 5.00 cm on each side and has a mass of 600.0 g. what is its density?
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The Ka of hydrazoic acid (HN3) is 1.9 × 10-5 at 25.0 °C. What is the pH of a 0.40 M aqueous solution of HN3?
siniylev [52]

Answer:

The pH of the solution is 2.56.

Explanation:

Given :

Concentration (c) = 0.40 M

Acid dissociation constant = K_a=1.9\times 10^{-5}

The equilibrium reaction for dissociation of HN_3 (weak acid) is,

                           HN_3+H_2O\rightleftharpoons N_3^{-}+H_3O^+

initially conc.         c                       0         0

At eqm.              c(1-\alpha)                c\alpha        c\alpha

Dissociation constant is given as:

K_a=\frac{(c\alpha)(c\alpha)}{c(1-\alpha)}

1.9\times 10^{-5}=\frac{(0.40\alpha)(0.40\alpha)}{0.40(1-\alpha)}

By solving the terms, we get value of (\alpha)}

\alpha=0.00686832

No we have to calculate the concentration of hydronium ion or hydrogen ion.

[H^+]=c\alpha=0.4\times 0.00686832=0.002747 M

Now we have to calculate the pH.

pH=-\log [H^+]

pH=-\log (0.002747)

pH=2.56

Therefore, the pH of the solution is, 2.56.

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