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Rina8888 [55]
2 years ago
10

The purpose of this guide is to help you write a clear and concise report that summarizes the lab I just completed. This lab sho

wed me how water carries rocks to a new location. For instance how the first model showed how a stream would act with light drizzle to downpour as I saw the outcomes were all if not completely then partially different I read the information that was given to me before I started each lab lesson and went on from there. Just say something that you think you could have done better in two to three sentences
topic: kentic energy
100 points for whole thing
Chemistry
2 answers:
Komok [63]2 years ago
6 0
I read this wrong lol.
Masja [62]2 years ago
3 0

Answer:

  The purpose of this guide is to help you write a clear and concise report that summarizes the lab I just completed.  This lab showed me how water carries rocks to a new location. For instance how the first model showed how a stream would act with light drizzle to downpour as I saw the outcomes were all if not completely then partially different  

            I read the information that was given to me before I started each lab lesson and went on from there.

Explanation:

:)

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atroni [7]

Answer:

A?

Explanation:

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2 years ago
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I need to know the answer to that
Tresset [83]

im not sure which one to answer, and i can hardly see the text.

8 0
3 years ago
1. Name the compound present in a sample of dry air.
aev [14]

Answer:

not air

Explanation:

I think so

hahaha

7 0
2 years ago
38.25 grams of silicon is combined with 14.33 grams of nitrogen gas. How many grams of silicon nitride can be formed if nitrogen
zhuklara [117]
3Si + 2N2 --> Si3N4 (as given) 

n(Si) = m/MM = 38.25/28.085 = 1.3619 mol
n(N2) = 14.33/2*14.007 = 0.5115 mol

Therefore, N2 is limiting and Si is in excess 
The molar ratio of 2N2:Si3N4 is 2:1 
So, 0.0575 mol of silicon nitride is formed (dividing 0.5115 by 2) 

m of silicon nitride= n*mm = 0.0575*140.283 = 8.06627... g 
= 8.066g (4 significant figures) 

(hopefully it is right, but double check in case i did something wrong) :) 
6 0
3 years ago
The energy required to ionize boron is 801 kJ/mol. You may want to reference (Pages 93 - 98) Section 2.5 while completing this p
earnstyle [38]

Answer:

The frequency is  f =  2,01 * 10^{15} \  Hz

Explanation:

From the question we are told that

   The energy required to ionize boron is E_b  =  801 KJ/mol

Generally the ionization energy of boron pre atom is mathematically represented as

     E_a  =  \frac{E_b}{N_A}

Here  N_A is the Avogadro's constant with value N_A  =  6.022*10^{23}

So

      E_a  =  \frac{801}{6.022*10^{23}}

=>     E_a  =  1.330 *10^{-18} \  J/atom

Generally the energy required to liberate one electron from an atom is equivalent to the ionization energy per atom and this mathematically represented as

       E =  hf  =  E_a

=>     hf  =  E_a

Here h is the Planks constant with value h = 6.626 *10^{-34}

So

       f =  \frac{1.330 *10^{-18}}{ 6.626 *10^{-34}}

=>      f =  2,01 * 10^{15} \  Hz

8 0
2 years ago
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