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horsena [70]
3 years ago
5

What did Lorenzo Romano Amedeo Carlo Avogadro theorize in 1811?

Chemistry
2 answers:
-BARSIC- [3]3 years ago
8 0

Answer:

He theorized that equal volumes of gases at the same temperature and pressure contain equal numbers of molecules.

Explanation:

In 1811, Avogadro published an article in a scientific journal, where he distinguished between molecules and atoms. He argued (contrary to what was thought) that in the case of water, the hydrogen and oxygen "atoms" were actually "molecules." One molecule of oxygen would react with two molecules of hydrogen (H2O).

Thus he proclaimed his famous hypothesis: "Equal volumes of any gases contain the same number of molecules when measured under the same conditions of temperature and pressure."

wlad13 [49]3 years ago
3 0

Avogadro's law, which states that equal volumes of gases under the same conditions of temperature and pressure will contain equal numbers of molecules.

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Using the van der Waals equation, the pressure in a 22.4 L vessel containing 1.00 mol of neon gas at 100 °C is ________ atm. (a
svetoff [14.1K]

Answer:

The answer to your question is        P = 1.357 atm

Explanation:

Data

Volume = 22.4 L

1 mol

temperature = 100°C

a = 0.211 L² atm

b = 0.0171 L/mol

R = 0.082 atmL/mol°K

Convert temperature to °K

Temperature = 100 + 273

                      = 373°K

Formula

               (P + \frac{a}{v^{2}} )(v - b) = RT

Substitution

               (P + \frac{0.211}{22.4})(22.4 - 0.0171) = (0.082)(373)

Simplify

               (P + 0.0094)(22.3829) = 30.586

Solve for P

                           P + 0.0094 = \frac{30.586}{22.3829}

                           P + 0.0094 = 1.366

                                 P = 1.336 - 0.0094

                                P = 1.357 atm

7 0
3 years ago
What is inside of a galactic center? (Inner bulge/bar of a galaxy) What kind of gases does it contain?
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3 years ago
Which lists the waves in order of frequency, from highest to lowest?
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Answer:

C

Explanation:

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7 0
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An insulated container contains 0.3 kg of water at 20 degrees C. An alloy with a mass of 0.090 kg and an initial temperature of
Lorico [155]

Answer:

The specific heat of the alloy is 2.324 J/g°C

Explanation:

<u>Step 1:</u> Data given

Mass of water = 0.3 kg = 300 grams

Temperature of water = 20°C

Mass of alloy = 0.090 kg

Initial temperature of alloy = 55 °C

The final temperature = 25°C

The specific heat of water = 4.184 J/g°C

<u>Step 2:</u> Calculate the specific heat of alloy

Qlost = -Qwater

Qmetal = -Qwater

Q = m*c*ΔT

m(alloy) * c(alloy) * ΔT(alloy) = -m(water)*c(water)*ΔT(water)

⇒ mass of alloy = 90 grams

⇒ c(alloy) = the specific heat of alloy = TO BE DETERMINED

⇒ ΔT(alloy) = The change of temperature = T2 - T1 = 25-55 = -30°C

⇒ mass of water = 300 grams

⇒ c(water) = the specific heat of water = 4.184 J/g°C

⇒ ΔT(water) = The change of temperature = T2 - T1 = 25 - 20 = 5 °C

90 * c(alloy) * -30°C = -300 * 4.184 J/g°C * 5°C

c(alloy) = 2.324 J/g°C

The specific heat of the  alloy is 2.324 J/g°C

3 0
3 years ago
According to the MyPyramid plan, which foods should be the smallest portion of a teen’s diet?
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The answer is GRAINS 


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2 years ago
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