Answer:
400.7886829 rad/s
Explanation:
First we have to turn our 0.35 rev/s into rad/s using the equation
(Xrev/s)*2pi=Xrad/s we can plug in .35*2pi=.7pi rad/s
Now we can us the equation m_1*v_1*r_1^2=m_1*v_2*r_2^2 we can plug in the given. Because the mass remains the same we can cross it off of both sides giving us just: v_1*r_1^2=v_2*r_2^2
(.7pi)*(.54)^2=(v_2)*(.04)^2
(.20412pi)=(v_2)*(.0016) [.20412pi=.6412618925]
then using division on both sides we get
(.6412618925/.0016)=v_2=400.79rad/s(This answer is rounded to the nearest hundreth)
See you in Mr.K's class tomorrow! -Ruben
Average speed = total distance/total time taken
The Atwood's machine is in motion starting from rest, then Vf = Vo + a(t).
<span>Final Velocity is given as 6.7 m/s and the time is 1.9 s thus 6.7= 0+ a(1.9) </span>
<span>then a = 6.7/1.9 = 3.526 m/s². </span>
<span>The Atwood's Machine also has the formula d= distance = 1/2a(t²) </span>
<span>distance given is 6.365 m , then 6.365 = 1/2 a (1.9)², </span>
<span>a = 3.526 m/s² the same acceleration. </span>
<span>a= g(m1-m2) / m1+m2) </span>
<span>m1a + m2a = m1g - m2g </span>
<span>m1a - m1g = -m2g - m2a </span>
<span>3.526 m1 - 9.81 m1 = -9.81m2 - 3.526 m2 </span>
<span>-6.28 m1 = -13.34 m2 </span>
<span>0.47 m1= m2 </span>
<span>if 24J = 1/2mv² </span>
<span>then 24J = 1/2 m1 ( 6.7)² </span>
<span>48/ 44.89 = m1 </span>
<span>1.069 kg = m1 , then </span>
<span>0.47(1.069) = m2 </span>
<span>0.503 kg = m2</span>
Answer:
E = 1.711 MeV
Explanation:
From the law of the conservation of energy:
where,
the kinetic energy of positron and electron = 1.2 MeV
Rest energy of the electron and the positron = 0.511 MeV
E = Energy of Photon = ?
Therefore,
<u>E = 1.711 MeV</u>
Answer:
Work is measured as the product of force and the displacement in the direction of the force. Work = force × displacement in the direction of the force.
