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dexar [7]
3 years ago
8

Ike's bikes requires 25% of the cost as a down payment for a new mountain bike . what fraction of the cost is this percent

Mathematics
2 answers:
Elanso [62]3 years ago
6 0
The answer is 1/4.......
Nataliya [291]3 years ago
4 0
25/100 or 1/4 is the down payment.
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2x+5y when x-3 and y -2
kolezko [41]

Answer:

-16

Step-by-step explanation:

2*-3+5*-2=-16 Hope this helps :D

Please mark brainliest

8 0
2 years ago
If a study determines the difference in average salary for subpopulations of people with blue eyes and people with brown eyes is
svp [43]
Unlikely to have ????
8 0
3 years ago
Can some explain how to do this?
zepelin [54]

Answer:

  • Exact Area = 210.25pi - 210
  • Approximate Area = 450.185

The units for the area are in square inches or in^2. The approximate value shown above is when using pi = 3.14

=============================================================

Explanation:

Use the pythagorean theorem to find the length of the hypotenuse

  • a = 20
  • b = 21
  • c = unknown

a^2 + b^2 = c^2

20^2 + 21^2 = c^2

400 + 441 = c^2

c^2 = 841

c = sqrt(841)

c = 29

The hypotenuse is 29 inches long. This is the diameter of the circle. Half of that is the radius at r = d/2 = 29/2 = 14.5 inches.

The area of the circle is...

A = pi*r^2

A = pi*(14.5)^2

A = pi*210.25

A = 210.25pi

Which is exact in terms of pi

We'll subtract off the triangular region as this isn't shaded in. The area of the triangle is base*height/2 = 20*21/2 = 420/2 = 210 square inches.

So the shaded region is therefore 210.25pi - 210 square inches

This approximates to 210.25*3.14 - 210 = 450.185 when using the approximation pi = 3.14; use more decimal digits of pi to get a more accurate value.

4 0
3 years ago
the diameter d in inches of a rope required to lift a weight of w tons is given by the function d = 10w π . How much weight can
faltersainse [42]

Answer:

wkldd

Step-by-step explanation:

5 0
3 years ago
Calculate the average rate of change over the interval 2
Morgarella [4.7K]

Answer:

Average rate of change over the interval 2<= x <= 5:

y = 3x + 5:        3

y = 3x^2 + 1:     21

y = 3^x:             78

<u />

Step-by-step explanation:

2<= x <= 5

Average rate of change over the interval 2<= x <= 5:

<u>y = 3x + 5</u>

y(5) = 3(5) + 5 = 20

y(2) = 3(2) + 5 = 11

Average rate of change = (20 - 11)/(5-2) = 9/3 = <u>3</u>

<u />

<u>y = 3x^2 + 1</u>

y(5) = 3(5^2) + 1 = 75 + 1 = 76

y(2) = 3(2^2) + 1= 13

Average rate of change = (76 - 13)/(5-2) = 63/3 = <u>21</u>

<u />

<u>y = 3^x</u>

y(5) = 3^5 = 243

y(2) = 3^2 =9

Average rate of change = (243-9)/(5-2) = 234/3 =<u> 78</u>

8 0
3 years ago
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