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ladessa [460]
4 years ago
12

Which of the following statements about current are true? (i) In metal wires,it is the negative charges (Le, the electrons) that

move in response to an applied voltage. (ii) By historic convention, circuit diagrams are drawn showing the direction of a "conventional current' as if it were positive charges that move (even though they do not).(iii) The "conventional current" runs in the opposite direction to the actual motion of the electrons. a.Only statement (ii) is true.b.Only statements (i) and (lil) are true.c.Only statement (i) is true.d.All three statements are true.
Physics
1 answer:
IRINA_888 [86]4 years ago
5 0

Answer:

d. All three statements are true.

Explanation:

In the metals the electrons are the charge carriers and they are the only mobile charges causing the flow of current when subjected to potential difference.

The electrons being negatively lead to the flow of current in opposite direction. The direction of the current is opposite to the direction of the negative charges.

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When a garden hose with an output diameter of 20 mm is directed straight upward, the stream of water rises to a height of 0.13m
SpyIntel [72]

Answer: h = 0.52m

Explanation:

Using the equation of out flow;

A1 × V1 = A2 ×V2

Where A1 = area of the first nozzle

A2 = area of the second nozzle

V1= velocity of flow out from the first nozzle

V2 = velocity of flow out from 2nd nozzle

But AV= area of nozzle × velocity of water = volume of water per second(m³/s).

Now we can set A×V = Area of nozzle × height of rise.

Henceb A1× h1 = A2 × h2 ( note the time cancel on both sides)

D1 = 20mm= 0.02m; h1 = 0.13m

D2 = 10mm = 0.01m; h2= ?

h2 = π(D1/2)²× h1 /π(D2/2)²

h2 = (0.02/2)² × 0.13/(0.01/2)²

= (0.01)² ×0.13 /(0.005)²

= 1.3 × 10^-5/(5 × 10^-3)²

= 1.3 × 10^-5/25 × 10^-6

= (1.3/25) 10^-5 × 10^6

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7 0
3 years ago
Two objects, one having twice the mass of the other, are initially at rest. Two forces, one twice as big as the other, act on th
Elodia [21]

<em><u>Note: There is no image to take as a reference, so I'm assuming F2 directed to the right and F1 to the left, and F2=2F1</u></em>

Answer:

\displaystyle a=\frac{F}{3M}

<em>to the right</em>

Explanation:

<u>Net Force</u>

When several forces are applied to a particle or a system of particles, the net force is the sum of them all, considering each force as a vector. As for the second Newton's law, the total force equals the product of the mass by the acceleration of the system:

\vec F_n=m\cdot \vec a

If the net force is zero, then the system of particles keeps at rest or at a constant velocity.

The system of particles described in the question consists of two objects of masses m1=M and m2, where

m_2=2m_1=2M

Two forces F1=F and F2 act individually on each object in opposite directions and

F_2=2F_1=2F

We don't get to see any image to know where the forces are applied to, so we'll assume F2 to the right and F1 to the left.

The net force of the system of particles is

F_n=2F-F=F

The mass of the system is

m_t=m_1+m_2=3M

Thus, the acceleration of the center of mass of the system is

\displaystyle a=\frac{F}{3M}

Since F2 is greater than F1, the direction of the acceleration is to the right.

Note: If the forces were opposite than assumed, the acceleration would be to the left

6 0
3 years ago
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