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noname [10]
3 years ago
13

A horizontal force of magnitude 34.0 n pushes a block of mass 3.93 kg across a floor where the coefficient of kinetic friction i

s 0.565. (a) how much work is done by that applied force on the block-floor system when the block slides through a displacement of 3.22 m across the floor? (b) during that displacement, the thermal energy of the block increases by 37.2 j. what is the increase in thermal energy of the floor? (c) what is the increase in the kinetic energy of the block?
Physics
1 answer:
Katyanochek1 [597]3 years ago
5 0
Some dogs may inherit a susceptibility to epilepsy.
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Answer:

W = 46 J

Explanation:

We need to find the angle between the two vectors Force vector and displacement vector.

First we will find the angle α of the force vector

tan\alpha =\frac{1}{8} \\\\\\alpha =7.125 deg\\

Then we find the angle β of the displacement vector

tan\beta=\frac{2}{6} \\\\beta = 18.43 deg\\

With these two angles we can find the angle between the two vectors

∅ = α + β = 25.56 deg

The definition of work is given by the expression

W=F*d*cos (theta)

The absolute value of F will be:

F=\sqrt{8^{2}+1^{2}  } \\F= 8.06 N

The absolute value of d will be:

d=\sqrt{(6 )^{2}+(2)^{2}  } \\d= 6.32m\\

Now we have:

W=8.06*6.32*cos(25.56)\\W=46 J

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Imagine that you drop an object of 10 kg, how much will be the acceleration and
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