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sveticcg [70]
3 years ago
15

Y = x —6x+8 The equation above represents a parabola in the xy-plane. Which of the following equivalent forms of the equation di

splays the x-intercepts of the parabola as constants or coefficients?
Mathematics
1 answer:
forsale [732]3 years ago
3 0

Answer:

y=(x-4)(x-2)

Step-by-step explanation:

Consider the given equation

y=x^2-6x+8

Factor form of a parabola: It displays the x-intercepts.

y=a(x-p)(x-q)          .... (1)

where, a is a constant and, p and q are x-intercepts.

So, we need to find the factored form of the given equation.

Splinting the middle term we get

y=x^2-4x-2x+8

y=x(x-4)-2(x-4)

y=(x-4)(x-2)         .... (2)

On comparing (1) and (2) we get

p=4,q=2

It means x-intercepts of the given parabola are 4 and 2.

Therefore, equivalent forms of the equation is y=(x-4)(x-2).

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Julie is tracking the growth of a plant for a science project. The height of the plant on the 2nd day she measured was 8 inches
kvv77 [185]

Answer:

Step-by-step explanation:

The relationship is linear, so the plant grows the same amount each day.

The height on the 2nd day was 8 inches:

h₂ = 8

The height on the 7th day was 20.5 inches:

h₇ = h₂ + (7-2)d = 8 + 5d = 20.5

d = 2.5

The plant grows 2.5 inches each day.

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3 years ago
Using Heron’s formula, calculate the area of the parallelogram to the nearest tenth of a square unit.
11Alexandr11 [23.1K]

Answer:

the area = 36.7

Step-by-step explanation:

3 0
3 years ago
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In an arithmetic sequence, a17 = -40 and
Viktor [21]

Answer:

Tn = 2Tn-1 - Tn-2

Step-by-step explanation:

Before we can generate the recursive sequence, we need to find the nth term of the given sequence.

nth term of an AP is given as:

Tn = a+(n-1)d

If a17 = -40

T17 = a+(17-1)d = -40

a+16d = -40 ...(1)

If a28 = -73

T28 = a+(28-1)d = -73

a+27d = -73 ...(2)

Solving both equations simultaneously using elimination method.

Subtracting 1 from 2 we have:

27d - 16d = -73-(-40)

11d = -73+40

11d = -33

d = -3

Substituting d = -3 into 1

a+16(-3) = -40

a - 48 = -40

a = -40+48

a = 8

Given a = 8, d = -3, the nth term of the sequence will be

Tn = 8+(n-1) (-3)

Tn = 8+(-3n+3)

Tn = 8-3n+3

Tn = 11-3n

Given Tn = 11-3n and d = -3

Tn-1 = Tn - d... (3)

Tn-1 = 11-3n +3

Tn-1 = 14-3n

Tn-2 = Tn-2d...(4)

Tn-2 = 11-3n-2(-3)

Tn-2 = 11-3n+6

Tn-2 = 17-3n

From 3, d = Tn - Tn-1

From 4, d = (Tn - Tn-2)/2

Equating both common difference

(Tn - Tn-2)/2 = Tn - Tn-1

Tn - Tn-2 = 2(Tn - Tn-1)

Tn - Tn-2 = 2Tn-2Tn-1

2Tn-Tn = 2Tn-1 - Tn-2

Tn = 2Tn-1 - Tn-2

The recursive formula will be

Tn = 2Tn-1 - Tn-2

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Answer:

Step-by-step explanation:

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(CO 3) A survey indicates that shoppers spend an average of 22 minutes with a standard deviation of 8 minutes in your store and
padilas [110]

Answer: 0.60

Step-by-step explanation:

Given: Mean : \mu = 22\text{ minutes}

Standard deviation : \sigma = 8\text{ minutes}

The formula to calculate z is given by :-

z=\dfrac{x-\mu}{\sigma}

For x= 20 minutes

z=\dfrac{22-20}{8}=0.25

The P Value =P(z

Hence, the probability that a randomly selected shopper will spend less than 20 minutes in the store= 0.60

5 0
4 years ago
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