Answer:
For vector u, x component = 10.558 and  y component =12.808
unit vector = 0.636 i+ 0.7716 j
For vector v, x component = 23.6316 and y component = -6.464
unit vector = 0.9645 i-0.2638 j
Explanation:
Let the vector u has magnitude 16.6
u makes an angle of 50.5° from x axis 
So 
Vertical component 
So vector u will be u = 10.558 i+12.808 j
Unit vector 
Now in second case let vector v has a magnitude of 24.5
Making an angle with -15.3° from x axis 
So horizontal component 
Vertical component 
So vector v will be 23.6316 i - 6.464 j
Unit vector of v 
 
        
             
        
        
        
The position vector can be
transcribed as:
A<span> = 6 i + y j  
                     
  </span>
i <span>points in the x-direction and j points
in the y-direction.</span>
The magnitude of the
vector is its dot product with itself:
<span>|A|2 = A·A</span>
<span>102  = (6 i +
y j)•(6 i+ y j)        
   Note that i•j = 0, and  i•i  = j•j =
1 </span>
<span>100  = 36 + y2  
    </span>
<span>64    = y2</span>
<span>get the square root of 64 = 8</span>
<span>The vertical component of the vector is 8 cm.</span>
 
        
             
        
        
        
"60 kg" is not a weight.  It's a mass, and it's always the same 
no matter where the object goes.
The weight of the object is    
                                 (mass) x (gravity in the place where the object is) .
On the surface of the Earth,
                   Weight = (60 kg) x (9.8 m/s²)
                                =      588 Newtons.
Now, the force of gravity varies as the inverse of the square of the distance from the center of the Earth.
On the surface, the distance from the center of the Earth is 1R.
So if you move out to  5R  from the center, the gravity out there is
                    (1R/5R)²  =  (1/5)²  =  1/25  =  0.04 of its value on the surface.
The object's weight would also be 0.04 of its weight on the surface.
                 (0.04) x (588 Newtons)  =  23.52 Newtons.
Again, the object's mass is still 60 kg out there.
___________________________________________
If you have a textbook, or handout material, or a lesson DVD,
or a teacher, or an on-line unit, that says the object "weighs" 
60 kilograms, then you should be raising a holy stink.  
You are being planted with sloppy, inaccurate, misleading 
information, and it's going to be YOUR problem to UN-learn it later.
They owe you better material.
        
             
        
        
        
The answer is vena cava 
Hope this helps !!