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stellarik [79]
2 years ago
5

Which scientist was the first to put the sun at the center of the "universe"?

Physics
1 answer:
lesya692 [45]2 years ago
6 0

Answer: C. Nicolas Copernicus

Explanation:

Copernicus's model of the universe (heliocentric theory) was refuting the long life geocentric theory (the Earth as the center of the universe) proposed by <u>Ptolemy</u> and accepted by the Catholic Church.

In this sense, <u>Ptolemy's model of the universe placed the Earth in the center of the known universe</u>, where our planet remains stationary while the other planets, the Moon and the Sun describe complicated orbits around it.

As Ptolemy was a respected astronomer and geographer, this idea was accepted for a long time, until Copernicus arrived with the new model.

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What do all elements in a column in the periodic table have in common?
JulsSmile [24]

Answer:

1, their atoms have the same number of valence electron. because valence electron determine the group of elements.

6 0
2 years ago
Potential difference is measured in units called
Masja [62]

Answer: Volt

Explanation:

5 0
3 years ago
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An electrically neutral model airplane is flying in a horizontal circle on a 2.0-m guideline, which is nearly parallel to the gr
amm1812

Answer:

q=3.5*10^-4

Explanation:

<u>concept:</u>

The force acting on both charges is given by the coulomb law:

F=kq1q2/r^2

the centripetal force is given by:

Fc=mv^2/r

The kinetic energy is given by:

KE=1/2mv^2

<u>The tension force:</u>

<u><em>when the plane is uncharged </em></u>

T=mv^2/r

T=2(K.E)/r

T=2(50 J)/r

T=100/r

<u><em>when the plane is charged </em></u>

T+k*|q|^2/r^2=2(K.E)charged/r

100/r+k*|q|^2/r^2=2(53.5 J)/r

q=√(2r[53.5 J-50 J]/k)                                          √= square root on whole

q=√2(2)(53.5 J-50 J)/8.99*10^9

q=3.5*10^-4

5 0
2 years ago
A block of mass 0.221 kg is placed on top of a light, vertical spring of force constant 5365 N/m and pushed downward so that the
Anvisha [2.4K]

Answer:

The maximum height above the point of release is 11.653 m.

Explanation:

Given that,

Mass of block = 0.221 kg

Spring constant k = 5365 N/m

Distance x = 0.097 m

We need to calculate the height

Using stored energy in spring

U=\dfrac{1}{2}kx^2...(I)

Using gravitational potential energy

U' =mgh....(II)

Using energy of conservation

E_{i}=E_{f}

U_{i}+U'_{i}=U_{f}+U'_{f}

\dfrac{1}{2}kx^2+0=0+mgh

h=\dfrac{kx^2}{2mg}

Where, k = spring constant

m = mass of the block

x = distance

g = acceleration due to gravity

Put the value in the equation

h=\dfrac{5365\times(0.097)^2}{2\times0.221\times9.8}

h=11.653\ m

Hence, The maximum height above the point of release is 11.653 m.

3 0
3 years ago
In terms of volume,how do ml &amp; cm3 relate to one another?
Keith_Richards [23]

1 milliliter = 1 cubic centimeter (cm^3)

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3 years ago
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