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Lina20 [59]
3 years ago
5

As light from air to water to glass, it will refract. The best explanation for this would be

Physics
2 answers:
oksano4ka [1.4K]3 years ago
8 0

The speed of a wave slows as it travels at different speed in different media. This is what causes the light to bend.

diamong [38]3 years ago
6 0
It d I took the test

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The three types of seismic waves produced by an earthquake are primary, secondary, and
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<span>The three types of seismic waves produced by an earthquake are primary, secondary, and (D.) surface.</span>
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3 years ago
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How is newton's first law used in basketball?
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Newton's first law of motion states that an object at rest tends to stay at rest, while an object in motion tends to stay in motion unless an external force acts upon it. This law appears in basketball when the player is shooting the ball. When the player is holding the ball, the ball is at rest but when a player shoots the ball, they use force to throw the ball in the hoop.

4 0
3 years ago
What's the momentum (in kg-m/s) of a cannonball with a mass of 21 moving with a velocity of 25 m/s?
lbvjy [14]
P=mv
P=21*25=525 kg*m/s
8 0
3 years ago
The massless spring of a spring gun has a force constant k=12~\text{N/cm}k=12 N/cm. When the gun is aimed vertically, a 15-g pro
ASHA 777 [7]

Answer:

0.011 m.

Explanation:

Energy stored in the spring = Energy of the projectile.

1/2ke² = mgh ................ Equation 1

Where k = spring constant, e = extension or compression, m = mass of the projectile, g = acceleration due to gravity, h = height.

make e the subject of the equation

e = √(2mgh/k)............................. Equation 2

Given: k = 12 N/cm = 1200 N/m, m = 15 g = 0.015 kg, h = 5.0 m

Constant: g = 9.8 m/s²

Substitute into equation 2

e = √(2×0.015×5/1200)

e = √(0.15/1200)

e = √(0.000125)

e = 0.011 m.

4 0
2 years ago
if a torque of 55.0 N/m is required and the largest force that can be exerted by you is 135 N what is th e length of the lever a
Whitepunk [10]

Answer:

r=0.41m

Explanation:

Torque is defined as the cross product between the position vector ( the lever arm vector connecting the origin to the point of force application) and the force vector.

\tau=r\times F

Due to the definition of cross product, the magnitude of the torque is given by:

\tau=rFsin\theta

Where \theta is the angle between the force and lever arm vectors. So, the length of the lever arm (r) is minimun when sin\theta is equal to one, solving for r:

r=\frac{\tau}{F}\\r=\frac{55\frac{N}{m}}{135N}\\r=0.41m

7 0
2 years ago
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