Answer:
equation gives the position at a specific time for an object with constant acceleration
Explanation:
equation gives the position at specific time for an object having constant acceleration. Constant acceleration is referred as the change of velocity with respect to the time is known as the acceleration, but when the velocity changes occurs at constant rate this rate is termed as the constant acceleration. The constant acceleration can never be zero. The velocity changes but that change occurs in the consistently. The acceleration is affected by the mass.
Answer:
Explanation:
Ignore air resistance
The horizontal velocity is
vx =19cos37.2 = 15.134 m/s
The ball travels 30 m in a time of
30 / 15.134 = 1.982 s
In that time, the ball will be at an altitude of
s = vy₀t + ½at²
s = 19sin37.2(1.982) + ½(-9.8)1.982² = 3.5137... m
so the ball clears the bar by
h = 3.5137 - 3.05 = 0.4637... = 0.46 m
Answer:
Left
Explanation:
The force is applied opposite of the acceleration.
Answer:
The answer is "Choice E".
Explanation:
In this situation the option e is right because its resistance decreases through time, however, the time is the same for the same reason, whereas the sphere deteriorates, somehow it travels shorter distances however if the air resistance becomes are using the amplitude of movement declines, that's why other choices were wrong.