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denpristay [2]
3 years ago
11

You find an unmarked blue laser on your way to physics class. When you get to class you realize you can determine the wavelength

of the laser by doing a double slit experiment. Shining the laser through a double slit with a slit separation of 0.342 mm on the wall 2.12 m away the first bright fringe is 2.80 mm from the center of the pattern. What is the wavelength
Physics
1 answer:
Afina-wow [57]3 years ago
5 0

Answer:

λ = 451.7 nm

Explanation:

The expression for the constructive interference of the double diffraction experiment is

          d sin θ = m λ

let's use trigonometry

          tan θ = y / L

   

how the experiment occurs at very small angles

          tan θ = sin θ / cos θ = sin θ

          sin θ = y / L

we substitute

         d y / L = m λ  

         λ = \frac{d \ y}{m \ L}

let's calculate

          λ = \frac{0.342 \ 10^{-3} \ 2.80 \ 10^{-3} }{1 \ 2.12 }

          λ = 4.51699 10⁻⁷ m

          λ = 4.517 10⁻⁷ m (109 nm / 1m)

          λ = 451.7 nm

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The same way to θ₂:

\frac{750*5}{G(\frac{\pi }{32})*0.5^{4}  } =\frac{T_{2}*6.3 }{G(\frac{\pi }{32})*d_{2} ^{4}  } \\T_{2} =9523.8d_{2} ^{4}

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