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aksik [14]
1 year ago
10

You are an astronomer and are making observations about a visible but faraway galaxy. Describe what evidence you could gather to

gain more information about (1) the galaxy's elemental composition and (2) it's motion relative to the Milky Way galaxy.
Physics
1 answer:
Pavel [41]1 year ago
6 0

Answer:

Chemical Composition

The chemical composition of the Universe is dominated by the hydrogen and helium produced in the Big Bang. The remaining 90 or so chemical elements are produced in stars and constitute only a few percent of the overall mass. Astronomers refer to these elements (all except hydrogen and helium) as metals, even though this includes elements such as carbon and oxygen which are not considered metals in the normal sense.

The abundance of metals with respect to hydrogen is known as the metallicity. While hydrogen and helium are found in high abundance throughout the Universe, the metallicity varies depending on the history of star formation in the region. The chemical composition of the Sun gives us some idea of the chemical composition of the solar neighbourhood:

Chemical composition of the Sun

Hydrogen 73%

Helium 25%

Oxygen 0.80%

Carbon 0.36%

Iron 0.16%

Neon 0.12%

Nitrogen 0.09%

Silicon 0.07%

Magnesium 0.05%

Sulphur 0.04%

Others combined 0.04%

This indicates that metals constitute only about 2% of the Sun’s mass.

The highest metallicities are found in the centres of galaxies. For example, near the centre of the Milky Way, stars with metallicities of up to three times the solar value have been observed. However, there are also stars with only 1/10,000th of the solar value. These stars formed early in the history of the Galaxy, before the interstellar medium (and subsequent generations of stars) became enriched in metals through the actions of other stars.

Although never more than a few percent by mass, the metals content of stars has a significant effect on their stellar evolution, with metal-rich stars being cooler, larger and longer-lived than metal-poor stars of the same mass. Both the length of time spent on the main sequence and the detail of post-main sequence evolution are significantly affected by a star’s metallicity.

To fully describe the chemical composition of stars (or galaxies) it is also necessary to define abundance ratios. These relate the relative abundances of metals to each other (e.g. the abundance ratio of magnesium to iron or carbon to oxygen). Astronomers use these abundance ratios to measure how long the object in question has been forming stars.

Both metallicities and abundance ratios are usually expressed in terms of the values for the Sun, and normally on a logarithmic scale.

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Two light bulbs are 2.0 m apart. From what distance can these light bulbs be marginally resolved by a small telescope with a 4.5
andrezito [222]

Answer:

R = 1.2295 10⁵  m

Explanation:

After reading your problem they give us the diameter of the lens d = 4.50 cm = 0.0450 m, therefore if we use the Rayleigh criterion for the resolution in the diffraction phenomenon, we have that the minimum separation occurs in the first minimum of diffraction of one of the bodies m = 1 coincides with the central maximum of the other body

            θ = 1.22 λ / D

where the constant 1.22 leaves the resolution in polar coordinates and D is the lens aperture

             

how angles are measured in radians

          θ = y / R

where y is the separation of the two bodies (bulbs) y = 2 m and R the distance from the bulbs to the lens

            \frac{y}{R} = 1.22 \frac{ \lambda}{D}

            R = \frac{ y \ D}{1.22 \lambda}

let's calculate

            R = \frac{ 2 \ 0.045}{ 1.22 \ 600 \ 10^{-9}}

            R = 1.2295 10⁵  m

3 0
2 years ago
How much work does this force do as the particle moves along the x-axis from x = 0 to x = l? express your answer in terms of the
nydimaria [60]
<h3><u>Answer</u>;</h3>

= F0 L ( 1 - 1/e )

<h3><u>Explanation;</u></h3>

Work done is given as the product of force and distance.

In this case;

Work done  = ∫︎ F(x) dx  

                    = F0 ∫︎ e^(-x/L) dx  

                    = F0 [ -L e^(-x/L) ] between 0 and L  

                    = F0 L ( 1 - 1/e )

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Explanation:

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\text{Acceleration}=\frac{d^2}{dt^2}\text{displacement}
So the dimensions of acceleration is LT^{-2}
Any answer that comes under that definition is correct.
6 0
3 years ago
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insens350 [35]

Venus is called Earth's "Twin" because Earth and Venus have almost the same mass, size, similar composition and they are neighboring planets. Some of most notable differences though between the two planets are their color, temperature, Earth's ability to support life and their atmosphere. Venus' atmosphere is about 100x thicker than Earth's, Earth can support life while Venus can not because Earth has water and plant life and Earth is a bright blue and green while Venus is more orange and red.

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