At A, coaster is only associated with potential energy.
At B, coaster is associated with kinetic as well as potential energy.
Since the track is frictionless, no energy will be lost when coaster reaches from point A to point B. Therefore, according to conservation of energy, total energy at A should be equal to total energy at B.
Total energy at A = mgh = mg(12)
Total energy at B = mgh+ mv²/2 = mg(2) + mv²/2
∴12mg = 2mg + mv²/2
∴(12g-2g)×2 = v²
∴v² = 20g
∴v = 14m/s.
Again conserving energy at points B and C.
Total energy at B = 2mg + m(14)²/2
Total energy at C = 4mg + mv²/2
∴2mg + m(14²)/2 = 4mg + mv²/2
Solving this you get,
v = 12.52 m/s.
Therefore, speed of roller coaster at point C is 12.52 m/s.
Answer:
Explanation:
Un motor aeronáutico o motor de aviación es aquel que se utiliza para la propulsión de aeronaves mediante la generación de una fuerza de arrastre.
Existen distintos tipos de motores de aviación, aunque se dividen en dos clases básicas: motores recíprocos —o de pistón— y de turbina de gas. Recientemente y gracias al desarrollo de la NASA y otras entidades, se ha comenzado también la producción de motores eléctricos para aeronaves que funcionen con energía solar fotovoltaica.
eso depende de el motor que cada avion tenga
Answer:
Value of magnitude of acceleration will be 
Explanation:
It is given that when a stone is dropped it takes 2.2 sec to reach the ground
(a) As the stone is dropped from the top of building
So its initial velocity
will be 0 m /sec
(b) As the stone is free falling and there is no external force applied on it so its acceleration will be equal to acceleration due to gravity
So value of magnitude of acceleration will be equal to
Its (a) and(a)for the other ? and the last one is (d)
Explanation:
It is given that,
Potential difference between the ends of a rod, V = 1.1 V
Length of the rod, l = 10 cm = 0.1 m
Area of cross section of the rod, 
The resistivity of graphite, 
(a) Let R is the resistance of the rod. It is given by :



So, the resistance of the rod is 0.833 ohms.
(b) Let I is the current flowing in the wire. It can be calculated using the Ohm's law as :


I = 1.32 A
(c) Let E is the electric field inside the rod. The electric field in terms of potential difference is given by :


E = 11 V/m
Hence, this is the required solution.