Need some help with homework but where doing it in class rn
1 answer:
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Distance covered was 12km, 7km then another 5 so just 7+5. As there is a right angle, we can use Pythagoras’ theorem to figure out the displacement. This would be x^2 = 7^2 + 5^2, so x=8.6km
Explanation:
Given that,
Velocity of the proton in lab frame
Velocity of the observer v= 0.8c
We need to calculate the velocity of the proton with respect to the observer
Using formula of velocity
(a). We need to calculate the total energy of the proton in the lab frame
Using formula of kinetic energy
Where, Proton mass energy = m₀c²
Put the value into the formula
(b). We need to calculate the kinetic energy of the proton in the observer
Using formula of kinetic energy
(c). We need to calculate the momentum of the proton with respect to observer
Using formula of momentum
We know that,
Proton mass energy = m₀c²
Hence, This is required solution.