Answer:
3360 N
Explanation:
In a first-class lever, the effort force and load force are on opposite sides of the fulcrum.
The lever is 5 m long. The load force is 1.50 m from the fulcrum, so the effort force must be 3.50 m from the fulcrum.
The torques are equal:
Fr = Fr
(1440 N) (3.5 m) = F (1.5 m)
F = 3360 N
You need to have the Mass and velocity
Answer:
See below...
Explanation:
Let’s express ⟨α⟩ in terms of ωi , ωf , and Δt. and torque in terms of It , ωi , ωf , and Δt.
STEP 1.
The rate of change of angular velocity is Angular acceleration.
The net change in angular velocity is Average angular acceleration divided by the elapsed time.
⟨α⟩ = ω f −ω i/Δt
STEP 2.
Torque is assumed this way
dω
τ = I ----
dt
.
⟨τ ⟩ = I t (ω f −ω i )/Δt
Answer:
Electric field, E = 0.064 V/m
Explanation:
It is given that,
Resistivity of silver wire,
Current density of the wire,
We need to find the magnitude of the electric field inside the wire. The relationship between electric field and the current density is given by :
E = 0.0636 V/m
or
E = 0.064 V/m
So, the magnitude of electric field inside the wire is 0.064 V/m. Hence, this is the required solution.
Answer:
Explanation:
Volume of lead object = volume of aluminium object = V
mass of lead object > mass of aluminium object
When both the objects immersed in water, the buoyant force acting on both the objects.
Buoyant force = Volume immersed x density of water x gravity
As the volume of both the objects is same, so the buoyant force acting on both the objects is same.
So, weight in air of lead object is more than the weight in air of aluminium object.