Answer:
The answer to your question is T2 = 580.5 °K
Explanation:
Data
Temperature 1 = T1 = 273°K
Pressure 1 = P1 = 388 kPa
Pressure 2 = P2 = 825 kPa
Temperature 2 = ?
Process
1.- Use the Gay-Lussac law
P1/T1 = P2/T2
-Solve for T2
T2 = P2T1/P1
-Substitution
T2 = (825)(273) / 388
-Simplification
T2 = 225225 / 388
-Result
T2 = 580.5 °K
Answer:
a = g
Explanation:
in this scenario, the diver is free-falling, hence his acceleration is equal to the pull of gravity
Answer:we can calculate the answer by following steps;
Explanation:
I think it's D.................................
Asexual propagation involves taking a part of one parent plant and causing it to regenerate itself into a new plant. The resulting new plant is genetically identical its parent. Asexual propagation involves the vegetative parts of a plant: stems, roots, or leaves.
The most common method for asexual propagation is from cuttings. A cutting is any detached plant part which, under favorable conditions for regeneration of missing parts, will produce a new plant identical to the parent plant.
Hope that help:)
